##// END OF EJS Templates
Identify position after a newline as the start of the next line...
Thomas Kluyver -
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@@ -108,6 +108,12 b' def test_line_at_cursor():'
108 108 assert line == "", ("Expected '', got %r" % line)
109 109 assert offset == 0, ("Expected '', got %r" % line)
110 110
111 # The position after a newline should be the start of the following line.
112 cell = "One\nTwo\n"
113 (line, offset) = line_at_cursor(cell, cursor_pos=4)
114 nt.assert_equal(line, "Two\n")
115 nt.assert_equal(offset, 4)
116
111 117 def test_muliline_statement():
112 118 cell = """a = (1,
113 119 3)
@@ -44,7 +44,7 b' def line_at_cursor(cell, cursor_pos=0):'
44 44 lines = cell.splitlines(True)
45 45 for line in lines:
46 46 next_offset = offset + len(line)
47 if next_offset >= cursor_pos:
47 if next_offset > cursor_pos:
48 48 break
49 49 offset = next_offset
50 50 else:
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