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@@ -1,128 +1,73 b'' | |||||
1 | """ |
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1 | """ | |
2 |
Module that allows latex output notebooks to be conditioned before |
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2 | Module that allows latex output notebooks to be conditioned before | |
3 | they are converted. |
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3 | they are converted. | |
4 | """ |
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4 | """ | |
5 | from __future__ import absolute_import |
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5 | from __future__ import absolute_import | |
6 |
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6 | |||
7 | # Configurable traitlets |
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7 | # Configurable traitlets | |
8 | from IPython.utils.traitlets import Unicode, Bool |
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9 |
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8 | |||
10 | # Needed to override transformer |
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9 | # Needed to override transformer | |
11 | from .transformers import (ActivatableTransformer) |
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10 | from .transformers import (ActivatableTransformer) | |
12 |
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11 | |||
13 | class LatexTransformer(ActivatableTransformer): |
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12 | class LatexTransformer(ActivatableTransformer): | |
14 | """ |
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13 | """ | |
15 | Converter for latex destined documents. |
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14 | Converter for latex destined documents. | |
16 |
""" |
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15 | """ | |
17 |
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16 | |||
18 | def cell_transform(self, cell, other, index): |
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17 | def cell_transform(self, cell, other, index): | |
19 | """ |
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18 | """ | |
20 | Apply a transformation on each cell, |
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19 | Apply a transformation on each cell, | |
21 |
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20 | |||
22 | receive the current cell, the resource dict and the index of current cell as parameter. |
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21 | receive the current cell, the resource dict and the index of current cell as parameter. | |
23 |
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22 | |||
24 | Returns modified cell and resource dict. |
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23 | Returns modified cell and resource dict. | |
25 | """ |
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24 | """ | |
26 | if hasattr(cell, "source") and cell.cell_type == "markdown": |
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25 | if hasattr(cell, "source") and cell.cell_type == "markdown": | |
27 |
cell.source = |
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26 | cell.source = remove_math_space(cell.source) | |
28 | return cell, other |
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27 | return cell, other | |
29 |
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28 | |||
30 |
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29 | def remove_math_space(text): | |
31 |
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30 | """ | |
32 |
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31 | Remove the space between latex math commands and enclosing $ symbols. | |
33 |
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32 | """ | |
34 |
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33 | |||
35 |
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34 | # First, scan through the markdown looking for $. If | |
36 |
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35 | # a $ symbol is found, without a preceding \, assume | |
37 |
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36 | # it is the start of a math block. UNLESS that $ is | |
38 |
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37 | # not followed by another within two math_lines. | |
39 |
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38 | math_regions = [] | |
40 |
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39 | math_lines = 0 | |
41 |
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40 | within_math = False | |
42 |
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41 | math_start_index = 0 | |
43 | index = 0 |
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42 | ptext = '' | |
44 |
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43 | last_character = "" | |
45 | for char in text: #Loop through each character in the text. |
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44 | skip = False | |
46 |
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45 | for index, char in enumerate(text): | ||
47 |
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46 | #Make sure the character isn't preceeded by a backslash | |
48 |
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47 | if (char == "$" and last_character != "\\"): | |
49 |
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48 | # Close the math region if this is an ending $ | ||
50 | # Close the math region if this is an ending $ |
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49 | if within_math: | |
51 |
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50 | within_math = False | |
52 |
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51 | skip = True | |
53 |
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52 | ptext = ptext+'$'+text[math_start_index+1:index].strip()+'$' | |
54 | else: |
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53 | math_regions.append([math_start_index, index+1]) | |
55 |
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56 | # Start a new math region |
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57 | within_math = True |
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58 | math_start_index = index |
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59 | math_lines = 0 |
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60 |
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61 | # If we are in a math region, count the number of lines parsed. |
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62 | # Cancel the math region if we find two line breaks! |
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63 | elif char == "\n": |
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64 | if within_math: |
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65 | math_lines += 1 |
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66 | if math_lines > 1: |
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67 | within_math = False |
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68 |
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69 | # Remember the last character so we can easily watch |
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70 | # for backslashes |
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71 | last_character = char |
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72 |
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73 | # Next index |
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74 | index += 1 |
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75 |
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76 | # Reset the index and last char |
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77 | index = 0 |
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78 |
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79 | # Now that we know what regions of the text are math and |
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80 | # what regions aren't, we can separate them into "blocks" |
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81 | text_blocks=[] |
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82 | math_blocks=[] |
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83 | was_math_block = False |
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84 | current_block = "" |
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85 | for char in text: |
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86 |
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87 | # Check if this is a math region. |
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88 | ismath = False |
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89 | for keypair in math_regions: |
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90 | if (keypair[0] <= index and index <= keypair[1]): |
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91 | ismath = True |
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92 |
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93 | # If the region type has changed since the last |
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94 | # iteration, commit all read characters to that |
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95 | # region type and reset the buffer. |
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96 | if (ismath and not was_math_block): |
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97 | was_math_block = True |
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98 | text_blocks.append(current_block) |
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99 | current_block="" |
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100 | elif ((not ismath) and was_math_block): |
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101 | was_math_block = False |
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102 | math_blocks.append(current_block) |
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103 | current_block="" |
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104 |
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105 | # Store the character |
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106 | current_block += char |
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107 |
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108 | # Next index |
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109 | index += 1 |
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110 |
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111 | # Save whatever remains in the buffer that hasn't yet been saved. |
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112 | if was_math_block: |
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113 | math_blocks.append(current_block) |
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114 | else: |
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115 | text_blocks.append(current_block) |
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116 |
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117 | # Recombine the regions, while processing every math region, removing |
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118 | # the spaces between the math and the $ symbols. |
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119 | output = "" |
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120 | for index in range(0,len(text_blocks) + len(math_blocks)): |
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121 | if index % 2 == 0: |
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122 | output += text_blocks[index/2] |
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123 | else: |
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54 | else: | |
124 | mathblock = math_blocks[(index -1)/2] |
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55 | # Start a new math region | |
125 | mathblock = mathblock[1:len(mathblock)-2] |
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56 | within_math = True | |
126 | output += "$" + mathblock.strip() + "$" |
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57 | math_start_index = index | |
127 | return output |
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58 | math_lines = 0 | |
128 |
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59 | # If we are in a math region, count the number of lines parsed. | ||
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60 | # Cancel the math region if we find two line breaks! | |||
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61 | elif char == "\n": | |||
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62 | if within_math: | |||
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63 | math_lines += 1 | |||
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64 | if math_lines > 1: | |||
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65 | within_math = False | |||
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66 | # Remember the last character so we can easily watch | |||
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67 | # for backslashes | |||
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68 | last_character = char | |||
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69 | if not within_math and not skip: | |||
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70 | ptext = ptext+char | |||
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71 | if skip: | |||
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72 | skip = False | |||
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73 | return ptext |
@@ -1,27 +1,25 b'' | |||||
1 | import io |
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1 | import io | |
2 | import nose.tools as nt |
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2 | import nose.tools as nt | |
3 | from nose.tools import nottest |
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3 | from nose.tools import nottest | |
4 |
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4 | |||
5 |
from converters import |
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5 | from converters.latex_transformer import remove_math_space | |
6 | lt = latex_transformer.LatexTransformer() |
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7 | lt.enabled = True |
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8 |
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6 | |||
9 | @nottest |
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7 | @nottest | |
10 | def test_space(input, reference): |
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8 | def test_space(input, reference): | |
11 |
nt.assert_equal( |
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9 | nt.assert_equal(remove_math_space(input),reference) | |
12 |
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10 | |||
13 |
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11 | |||
14 |
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12 | |||
15 | def test_evens(): |
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13 | def test_evens(): | |
16 | references = [ |
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14 | references = [ | |
17 | ('$e$','$e$'), |
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15 | ('$e$','$e$'), | |
18 | ('$ e $','$e$'), |
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16 | ('$ e $','$e$'), | |
19 | ('xxx$e^i$yyy','xxx$e^i$yyy'), |
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17 | ('xxx$e^i$yyy','xxx$e^i$yyy'), | |
20 | ('xxx$ e^i $yyy','xxx$e^i$yyy'), |
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18 | ('xxx$ e^i $yyy','xxx$e^i$yyy'), | |
21 | ('xxx$e^i $yyy','xxx$e^i$yyy'), |
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19 | ('xxx$e^i $yyy','xxx$e^i$yyy'), | |
22 | ('xxx$ e^i$yyy','xxx$e^i$yyy'), |
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20 | ('xxx$ e^i$yyy','xxx$e^i$yyy'), | |
23 | ('\$ e $ e $','\$ e $e$'), |
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21 | ('\$ e $ e $','\$ e $e$'), | |
24 | ] |
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22 | ] | |
25 |
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23 | |||
26 | for k,v in references : |
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24 | for k,v in references : | |
27 | yield test_space, k,v |
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25 | yield test_space, k,v |
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