upstream/ipython Files · IPython/core/tests/simpleerr.py

Avoid crashing if interrupt the kernel during completion....

Avoid crashing if interrupt the kernel during completion. This is likely due to completion taking too long, so just return what we have so far, and ignore the interrupt. closes

Fernando Perez - - Load All Authors

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             simpleerr.py
        
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      """Error script. DO NOT EDIT FURTHER! It will break exception doctests!!!"""

      import sys

      def div0():

          "foo"

          x = 1

          y = 0

          x/y

      def sysexit(stat, mode):

          raise SystemExit(stat, 'Mode = %s' % mode)

      def bar(mode):

          "bar"

          if mode=='div':

              div0()

          elif mode=='exit':

              try:

                  stat = int(sys.argv[2])

              except:

                  stat = 1

              sysexit(stat, mode)

          else:

              raise ValueError('Unknown mode')

      if __name__ == '__main__':

          try:

              mode = sys.argv[1]

          except IndexError:

              mode = 'div'

          bar(mode)

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				"""Error script. DO NOT EDIT FURTHER! It will break exception doctests!!!"""
				import sys

				def div0():
				"foo"
				x = 1
				y = 0
				x/y

				def sysexit(stat, mode):
				raise SystemExit(stat, 'Mode = %s' % mode)

				def bar(mode):
				"bar"
				if mode=='div':
				div0()
				elif mode=='exit':
				try:
				stat = int(sys.argv[2])
				except:
				stat = 1
				sysexit(stat, mode)
				else:
				raise ValueError('Unknown mode')

				if __name__ == '__main__':
				try:
				mode = sys.argv[1]
				except IndexError:
				mode = 'div'

				bar(mode)