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Avoid crashing if interrupt the kernel during completion....
Avoid crashing if interrupt the kernel during completion. This is likely due to completion taking too long, so just return what we have so far, and ignore the interrupt. closes #10733

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gui-qt.py
40 lines | 1009 B | text/x-python | PythonLexer
#!/usr/bin/env python
"""Simple Qt4 example to manually test event loop integration.
This is meant to run tests manually in ipython as:
In [5]: %gui qt
In [6]: %run gui-qt.py
Ref: Modified from http://zetcode.com/tutorials/pyqt4/firstprograms/
"""
from PyQt4 import QtGui, QtCore
class SimpleWindow(QtGui.QWidget):
def __init__(self, parent=None):
QtGui.QWidget.__init__(self, parent)
self.setGeometry(300, 300, 200, 80)
self.setWindowTitle('Hello World')
quit = QtGui.QPushButton('Close', self)
quit.setGeometry(10, 10, 60, 35)
self.connect(quit, QtCore.SIGNAL('clicked()'),
self, QtCore.SLOT('close()'))
if __name__ == '__main__':
app = QtCore.QCoreApplication.instance()
if app is None:
app = QtGui.QApplication([])
sw = SimpleWindow()
sw.show()
try:
from IPython.lib.guisupport import start_event_loop_qt4
start_event_loop_qt4(app)
except ImportError:
app.exec_()