##// END OF EJS Templates
test KernelManager.get_connection_info
test KernelManager.get_connection_info

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console.py
120 lines | 3.9 KiB | text/x-python | PythonLexer
"""Utility functions for interacting with the console"""
#-----------------------------------------------------------------------------
# Copyright (c) 2013, the IPython Development Team.
#
# Distributed under the terms of the Modified BSD License.
#
# The full license is in the file COPYING.txt, distributed with this software.
#-----------------------------------------------------------------------------
#-----------------------------------------------------------------------------
# Imports
#-----------------------------------------------------------------------------
# Used to determine python version
import sys
#-----------------------------------------------------------------------------
# Classes and functions
#-----------------------------------------------------------------------------
def input(prompt_text):
"""
Prompt the user for input.
The input command will change depending on the version of python
installed. To maintain support for 2 and earlier, we must use
raw_input in that case. Else use input.
Parameters
----------
prompt_text : str
Prompt to display to the user.
"""
# Try to get the python version. This command is only available in
# python 2 and later, so it's important that we catch the exception
# if the command isn't found.
try:
majorversion = sys.version_info[0]
except AttributeError:
majorversion = 1
# Use the correct function to prompt the user for input depending on
# what python version the code is running in.
if majorversion >= 3:
return input(prompt_text)
else:
return raw_input(prompt_text).decode(sys.stdin.encoding)
def prompt_boolean(prompt, default=False):
"""
Prompt the user for a boolean response.
Parameters
----------
prompt : str
prompt to display to the user
default : bool, optional
response to return if none is given by the user
"""
response = input(prompt)
response = response.strip().lower()
#Catch 1, true, yes as True
if len(response) > 0 and (response == "1" or response[0] == "t" or response[0] == "y"):
return True
#Catch 0, false, no as False
elif len(response) > 0 and (response == "0" or response[0] == "f" or response[0] == "n"):
return False
else:
return default
def prompt_dictionary(choices, default_style=1, menu_comments={}):
"""
Prompt the user to chose one of many selections from a menu.
Parameters
----------
choices : dictionary
Keys - choice numbers (int)
Values - choice value (str), this is what the function will return
default_style : int, optional
Choice to select if the user doesn't respond
menu_comments : dictionary, optional
Additional comments to append to the menu as it is displayed
in the console.
Keys - choice numbers (int)
Values - comment (str), what will be appended to the
corresponding choice
"""
# Build the menu that will be displayed to the user with
# all of the options available.
prompt = ""
for key, value in choices.iteritems():
prompt += "%d %s " % (key, value)
if key in menu_comments:
prompt += menu_comments[key]
prompt += "\n"
# Continue to ask the user for a style until an appropriate
# one is specified.
response = -1
while (not response in choices):
try:
text_response = input(prompt)
# Use default option if no input.
if len(text_response.strip()) == 0:
response = default_style
else:
response = int(text_response)
except ValueError:
print("Error: Value is not an available option. 0 selects the default.\n")
return choices[response]