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Refuse to install event loop hooks when not using `prompt_toolkit` (#14132)...
Refuse to install event loop hooks when not using `prompt_toolkit` (#14132) Without this, `%gui` is effectively a no-op but the user thinks it works. For example. If running `ipython`: ``` In [1]: import matplotlib; matplotlib.use('QtAgg'); from matplotlib import pyplot; pyplot.ion(); pyplot.plot([1, 2, 3, 4]) Installed qt6 event loop hook. Out[1]: [<matplotlib.lines.Line2D at 0x1ba2f59d2a0>] ``` The window appears and responds as expected. If running `ipython --simple-prompt`, the user would see the same output, when in fact no event loop hook was installed since it's not supported without `prompt_toolkit`. The resulting Qt window is unresponsive because the event loop is not running, i.e. with `--simple-prompt`, Qt windows should block (but `pyplot` doesn't/can't know to do that) With this PR, the user will see: ``` In [1]: import matplotlib; matplotlib.use('QtAgg'); from matplotlib import pyplot; pyplot.ion(); pyplot.plot([1, 2, 3, 4]) Cannot install event loop hook for "qt" when running with `--simple-prompt`. NOTE: Tk is supported natively; use Tk apps and Tk backends with `--simple-prompt`. Out[1]: [<matplotlib.lines.Line2D at 0x170be0c0310>] ``` They'll still get an unresponsive Qt window, but they'll at least be told this can't work (while anything using Tk will work just fine).

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tclass.py
34 lines | 921 B | text/x-python | PythonLexer
"""Simple script to be run *twice*, to check reference counting bugs.
See test_run for details."""
import sys
# We want to ensure that while objects remain available for immediate access,
# objects from *previous* runs of the same script get collected, to avoid
# accumulating massive amounts of old references.
class C(object):
def __init__(self,name):
self.name = name
self.p = print
self.flush_stdout = sys.stdout.flush
def __del__(self):
self.p('tclass.py: deleting object:',self.name)
self.flush_stdout()
try:
name = sys.argv[1]
except IndexError:
pass
else:
if name.startswith('C'):
c = C(name)
#print >> sys.stderr, "ARGV:", sys.argv # dbg
# This next print statement is NOT debugging, we're making the check on a
# completely separate process so we verify by capturing stdout:
print('ARGV 1-:', sys.argv[1:])
sys.stdout.flush()