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don't use combine option on ucs package...
don't use combine option on ucs package Caused problems with unicode. It seems f9c32fcee337b6560ec31e25fba04cae6021b74a was actually the right fix for the original error, not faf51b858a8c5757944822ee1d75c11367e994f. closes #5129

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r13353:0ca701d5
r15347:376ac6d2
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nbbase.py
73 lines | 1.9 KiB | text/x-python | PythonLexer
"""The basic dict based notebook format.
Authors:
* Brian Granger
"""
#-----------------------------------------------------------------------------
# Copyright (C) 2008-2011 The IPython Development Team
#
# Distributed under the terms of the BSD License. The full license is in
# the file COPYING, distributed as part of this software.
#-----------------------------------------------------------------------------
#-----------------------------------------------------------------------------
# Imports
#-----------------------------------------------------------------------------
import pprint
import uuid
from IPython.utils.ipstruct import Struct
from IPython.utils.py3compat import unicode_type
#-----------------------------------------------------------------------------
# Code
#-----------------------------------------------------------------------------
class NotebookNode(Struct):
pass
def from_dict(d):
if isinstance(d, dict):
newd = NotebookNode()
for k,v in d.items():
newd[k] = from_dict(v)
return newd
elif isinstance(d, (tuple, list)):
return [from_dict(i) for i in d]
else:
return d
def new_code_cell(code=None, prompt_number=None):
"""Create a new code cell with input and output"""
cell = NotebookNode()
cell.cell_type = u'code'
if code is not None:
cell.code = unicode_type(code)
if prompt_number is not None:
cell.prompt_number = int(prompt_number)
return cell
def new_text_cell(text=None):
"""Create a new text cell."""
cell = NotebookNode()
if text is not None:
cell.text = unicode_type(text)
cell.cell_type = u'text'
return cell
def new_notebook(cells=None):
"""Create a notebook by name, id and a list of worksheets."""
nb = NotebookNode()
if cells is not None:
nb.cells = cells
else:
nb.cells = []
return nb