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Merge pull request #3756 from minrk/wiredoc...
Merge pull request #3756 from minrk/wiredoc document the wire protocol in the messaging doc also update the digest scheme to use sha256 and make this configurable, since md5 is the previous default and has been shown to be bad. More messaging docs to update here: - [x] remove get/setattr on kernel - [x] remove crash messages - [x] completion requests do not behave as documented - [x] object_info is misdocumented (`name` is actually `oname` in object_info_request)

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Trapezoid Rule.ipynb
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Basic Numerical Integration: the Trapezoid Rule

A simple illustration of the trapezoid rule for definite integration:

$$ \int_{a}^{b} f(x)\, dx \approx \frac{1}{2} \sum_{k=1}^{N} \left( x_{k} - x_{k-1} \right) \left( f(x_{k}) + f(x_{k-1}) \right). $$
First, we define a simple function and sample it between 0 and 10 at 200 points
In [1]:
%matplotlib inline
import numpy as np
import matplotlib.pyplot as plt
In [2]:
def f(x):
    return (x-3)*(x-5)*(x-7)+85

x = np.linspace(0, 10, 200)
y = f(x)

Choose a region to integrate over and take only a few points in that region

In [3]:
a, b = 1, 9
xint = x[np.logical_and(x>=a, x<=b)][::30]
yint = y[np.logical_and(x>=a, x<=b)][::30]

Plot both the function and the area below it in the trapezoid approximation

In [4]:
plt.plot(x, y, lw=2)
plt.axis([0, 10, 0, 140])
plt.fill_between(xint, 0, yint, facecolor='gray', alpha=0.4)
plt.text(0.5 * (a + b), 30,r"$\int_a^b f(x)dx$", horizontalalignment='center', fontsize=20);
No description has been provided for this image

Compute the integral both at high accuracy and with the trapezoid approximation

In [5]:
from __future__ import print_function
from scipy.integrate import quad, trapz
integral, error = quad(f, 1, 9)
print("The integral is:", integral, "+/-", error)
print("The trapezoid approximation with", len(xint), "points is:", trapz(yint, xint))
The integral is: 680.0 +/- 7.54951656745e-12
The trapezoid approximation with 6 points is: 621.286411141