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Backport PR #6005: Changed right arrow key movement function to mirror left arrow key...
Backport PR #6005: Changed right arrow key movement function to mirror left arrow key Seems to solve Issue #5926 on this machine, and passing the test file locally. Changed from `cursor.movePosition` to `self._control.moveCursor`, the latter is what the left-arrow key uses. Also removed line 1373 which seems unnecessary and which prevents the cursor from moving at all. I'm not certain how to further test this to make sure nothing was broken.

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Using MPI with IPython Parallel.ipynb
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/ examples / Parallel Computing / Using MPI with IPython Parallel.ipynb

Simple usage of a set of MPI engines

This example assumes you've started a cluster of N engines (4 in this example) as part of an MPI world.

Our documentation describes how to create an MPI profile and explains basic MPI usage of the IPython cluster.

For the simplest possible way to start 4 engines that belong to the same MPI world, you can run this in a terminal:

ipcluster start --engines=MPI -n 4

or start an MPI cluster from the cluster tab if you have one configured.

Once the cluster is running, we can connect to it and open a view into it:

In [1]:
from IPython.parallel import Client
c = Client()
view = c[:]

Let's define a simple function that gets the MPI rank from each engine.

In [2]:
@view.remote(block=True)
def mpi_rank():
    from mpi4py import MPI
    comm = MPI.COMM_WORLD
    return comm.Get_rank()
In [3]:
mpi_rank()
Out[3]:
[2, 3, 1, 0]

To get a mapping of IPython IDs and MPI rank (these do not always match), you can use the get_dict method on AsyncResults.

In [4]:
mpi_rank.block = False
ar = mpi_rank()
ar.get_dict()
Out[4]:
{0: 2, 1: 3, 2: 1, 3: 0}

With %%px cell magic, the next cell will actually execute entirely on each engine:

In [5]:
%%px
from mpi4py import MPI

comm = MPI.COMM_WORLD
size = comm.Get_size()
rank = comm.Get_rank()

if rank == 0:
   data = [(i+1)**2 for i in range(size)]
else:
   data = None
data = comm.scatter(data, root=0)

assert data == (rank+1)**2, 'data=%s, rank=%s' % (data, rank)
In [6]:
view['data']
Out[6]:
[9, 16, 4, 1]
In [6]: