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push() now swallows syntax errors and immediately produces a 'ready'...
push() now swallows syntax errors and immediately produces a 'ready' state. This is intended, as the invalid input may in fact be OK with ipython extensions, but that can only be ascertained by the kernel, so the client should send this right away to the kernel.

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growl.py
65 lines | 1.8 KiB | text/x-python | PythonLexer
# encoding: utf-8
"""
Utilities using Growl on OS X for notifications.
"""
#-----------------------------------------------------------------------------
# Copyright (C) 2008-2009 The IPython Development Team
#
# Distributed under the terms of the BSD License. The full license is in
# the file COPYING, distributed as part of this software.
#-----------------------------------------------------------------------------
#-----------------------------------------------------------------------------
# Imports
#-----------------------------------------------------------------------------
#-----------------------------------------------------------------------------
# Code
#-----------------------------------------------------------------------------
class IPythonGrowlError(Exception):
pass
class Notifier(object):
def __init__(self, app_name):
try:
import Growl
except ImportError:
self.g_notifier = None
else:
self.g_notifier = Growl.GrowlNotifier(app_name, ['kernel', 'core'])
self.g_notifier.register()
def _notify(self, title, msg):
if self.g_notifier is not None:
self.g_notifier.notify('core', title, msg)
def notify(self, title, msg):
self._notify(title, msg)
def notify_deferred(self, r, msg):
title = "Deferred Result"
msg = msg + '\n' + repr(r)
self._notify(title, msg)
return r
_notifier = None
def notify(title, msg):
pass
def notify_deferred(r, msg):
return r
def start(app_name):
global _notifier, notify, notify_deferred
if _notifier is not None:
raise IPythonGrowlError("this process is already registered with Growl")
else:
_notifier = Notifier(app_name)
notify = _notifier.notify
notify_deferred = _notifier.notify_deferred