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Don't use new subplots() call in matplotlib so tests pass with mpl 0.99
Don't use new subplots() call in matplotlib so tests pass with mpl 0.99

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interengine.py
43 lines | 1.3 KiB | text/x-python | PythonLexer
import sys
from IPython.parallel import Client
rc = Client()
rc.block=True
view = rc[:]
view.run('communicator.py')
view.execute('com = EngineCommunicator()')
# gather the connection information into a dict
ar = view.apply_async(lambda : com.info)
peers = ar.get_dict()
# this is a dict, keyed by engine ID, of the connection info for the EngineCommunicators
# connect the engines to each other:
view.apply_sync(lambda pdict: com.connect(pdict), peers)
# now all the engines are connected, and we can communicate between them:
def broadcast(client, sender, msg_name, dest_name=None, block=None):
"""broadcast a message from one engine to all others."""
dest_name = msg_name if dest_name is None else dest_name
client[sender].execute('com.publish(%s)'%msg_name, block=None)
targets = client.ids
targets.remove(sender)
return client[targets].execute('%s=com.consume()'%dest_name, block=None)
def send(client, sender, targets, msg_name, dest_name=None, block=None):
"""send a message from one to one-or-more engines."""
dest_name = msg_name if dest_name is None else dest_name
def _send(targets, m_name):
msg = globals()[m_name]
return com.send(targets, msg)
client[sender].apply_async(_send, targets, msg_name)
return client[targets].execute('%s=com.recv()'%dest_name, block=None)