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kernel heartbeat does not share zmq context with rest of the app...
kernel heartbeat does not share zmq context with rest of the app This prevents the heartbeat from ever waiting for the GIL, which could cause erroneous heartbeat failures.

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ipy_server.py
37 lines | 1023 B | text/x-python | PythonLexer
""" Simple TCP socket server that executes statements in IPython instance.
Usage:
import ipy_server
ipy_server.serve_thread(16455)
Now, to execute the statements in this ipython instance, open a TCP socket
(port 16455), write out the statements, and close the socket.
You can use e.g. "telnet localhost 16455" or a script to do this.
This is a bit like 'M-x server-start" or gnuserv in the emacs world.
"""
from IPython.core import ipapi
ip = ipapi.get()
import SocketServer
# user-accessible port
PORT = 8099
class IPythonRequestHandler(SocketServer.StreamRequestHandler):
def handle(self):
#print "connection from", self.client_address
inp = self.rfile.read().replace('\r\n','\n')
#print "Execute",inp
ip.runlines(inp)
def serve(port = PORT):
server = SocketServer.TCPServer(("", port), IPythonRequestHandler)
print "ipy_server on TCP port", port
server.serve_forever()
def serve_thread(port = PORT):
import thread
thread.start_new_thread(serve, (port,))