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Fix: openssh_tunnel did not parse port in `server`...
Fix: openssh_tunnel did not parse port in `server` Despite what the docstring of openssh_tunnel mentioned, it did not parse username in port in the `server` argument. This patch fixes the problem so that ipython client can connect to the server over port-forwarded ssh connection. For example, you can connect the client by the following code now:: c = Client('/path/to/ipcontroller-client.json', sshserver='me@localhost:1234')

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heartbeat.py
48 lines | 1.6 KiB | text/x-python | PythonLexer
"""The client and server for a basic ping-pong style heartbeat.
"""
#-----------------------------------------------------------------------------
# Copyright (C) 2008-2011 The IPython Development Team
#
# Distributed under the terms of the BSD License. The full license is in
# the file COPYING, distributed as part of this software.
#-----------------------------------------------------------------------------
#-----------------------------------------------------------------------------
# Imports
#-----------------------------------------------------------------------------
import socket
import sys
from threading import Thread
import zmq
from IPython.utils.localinterfaces import LOCALHOST
#-----------------------------------------------------------------------------
# Code
#-----------------------------------------------------------------------------
class Heartbeat(Thread):
"A simple ping-pong style heartbeat that runs in a thread."
def __init__(self, context, addr=(LOCALHOST, 0)):
Thread.__init__(self)
self.context = context
self.ip, self.port = addr
if self.port == 0:
s = socket.socket()
# '*' means all interfaces to 0MQ, which is '' to socket.socket
s.bind(('' if self.ip == '*' else self.ip, 0))
self.port = s.getsockname()[1]
s.close()
self.addr = (self.ip, self.port)
self.daemon = True
def run(self):
self.socket = self.context.socket(zmq.REP)
self.socket.bind('tcp://%s:%i' % self.addr)
zmq.device(zmq.FORWARDER, self.socket, self.socket)