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Update version requirement to 2.5, since that's what we're using anyway....
Update version requirement to 2.5, since that's what we're using anyway. Fixes https://bugs.launchpad.net/ipython/+bug/505090

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splitinput.py
83 lines | 2.6 KiB | text/x-python | PythonLexer
#!/usr/bin/env python
# encoding: utf-8
"""
Simple utility for splitting user input.
Authors:
* Brian Granger
* Fernando Perez
"""
#-----------------------------------------------------------------------------
# Copyright (C) 2008-2009 The IPython Development Team
#
# Distributed under the terms of the BSD License. The full license is in
# the file COPYING, distributed as part of this software.
#-----------------------------------------------------------------------------
#-----------------------------------------------------------------------------
# Imports
#-----------------------------------------------------------------------------
import re
#-----------------------------------------------------------------------------
# Main function
#-----------------------------------------------------------------------------
# RegExp for splitting line contents into pre-char//first word-method//rest.
# For clarity, each group in on one line.
# WARNING: update the regexp if the escapes in iplib are changed, as they
# are hardwired in.
# Although it's not solely driven by the regex, note that:
# ,;/% only trigger if they are the first character on the line
# ! and !! trigger if they are first char(s) *or* follow an indent
# ? triggers as first or last char.
# The three parts of the regex are:
# 1) pre: pre_char *or* initial whitespace
# 2) ifun: first word/method (mix of \w and '.')
# 3) the_rest: rest of line (separated from ifun by space if non-empty)
line_split = re.compile(r'^([,;/%?]|!!?|\s*)'
r'\s*([\w\.]+)'
r'(\s+.*$|$)')
# r'[\w\.]+'
# r'\s*=\s*%.*'
def split_user_input(line, pattern=None):
"""Split user input into pre-char/whitespace, function part and rest.
This is currently handles lines with '=' in them in a very inconsistent
manner.
"""
if pattern is None:
pattern = line_split
match = pattern.match(line)
if not match:
# print "match failed for line '%s'" % line
try:
ifun, the_rest = line.split(None,1)
except ValueError:
# print "split failed for line '%s'" % line
ifun, the_rest = line,''
pre = re.match('^(\s*)(.*)',line).groups()[0]
else:
pre,ifun,the_rest = match.groups()
# ifun has to be a valid python identifier, so it better be only pure
# ascii, no unicode:
try:
ifun = ifun.encode('ascii')
except UnicodeEncodeError:
the_rest = ifun + u' ' + the_rest
ifun = u''
#print 'line:<%s>' % line # dbg
#print 'pre <%s> ifun <%s> rest <%s>' % (pre,ifun.strip(),the_rest) # dbg
return pre, ifun.strip(), the_rest.lstrip()