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Update version requirement to 2.5, since that's what we're using anyway....
Update version requirement to 2.5, since that's what we're using anyway. Fixes https://bugs.launchpad.net/ipython/+bug/505090

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traceback_formatter.py
62 lines | 1.8 KiB | text/x-python | PythonLexer
/ IPython / kernel / core / traceback_formatter.py
# encoding: utf-8
"""Some formatter objects to extract traceback information by replacing
sys.excepthook()."""
__docformat__ = "restructuredtext en"
#-------------------------------------------------------------------------------
# Copyright (C) 2008 The IPython Development Team
#
# Distributed under the terms of the BSD License. The full license is in
# the file COPYING, distributed as part of this software.
#-------------------------------------------------------------------------------
#-------------------------------------------------------------------------------
# Imports
#-------------------------------------------------------------------------------
import traceback
class ITracebackFormatter(object):
""" Objects conforming to this interface will format tracebacks into other
objects.
"""
# The kind of formatter.
kind = 'traceback'
# The unique identifier for this formatter.
identifier = None
def __call__(self, exc_type, exc_value, exc_traceback):
""" Return a formatted representation of a traceback.
"""
raise NotImplementedError
class PlainTracebackFormatter(ITracebackFormatter):
""" Return a string with the regular traceback information.
"""
# The unique identifier for this formatter.
identifier = 'plain'
def __init__(self, limit=None):
# The maximum number of stack levels to go back.
# None implies all stack levels are returned.
self.limit = limit
def __call__(self, exc_type, exc_value, exc_traceback):
""" Return a string with the regular traceback information.
"""
lines = traceback.format_tb(exc_traceback, self.limit)
lines.append('%s: %s' % (exc_type.__name__, exc_value))
return '\n'.join(lines)