upstream/ipython Files · IPython/frontend/html/notebook/utils.py

regexp group in BatchLauncher, no Condor -verbose...

regexp group in BatchLauncher, no Condor -verbose Previously I used condor_submit -verbose so that I could pull the job id from the first line. However, when submitting many jobs it's silly to have to search through some many lines of output. Now we have a regexp for Condor that matches on the non-verbose output. Here the job_id is on the end of the output, so using grouping in our job_id_regexp becomes very useful. To account for this I have added a job_id_regexp_group property to the BatchLauncher and it's subclasses. The default of 0 means the whole regexp is matched - however now an integer can be passed in here to instead select a subgroup of the expression (see CondorLauncher and the mechanism will be clear).

Brian E. Granger - - Load All Authors

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      """Notebook related utilities

      Authors:

      * Brian Granger

      """

      #-----------------------------------------------------------------------------

      #  Copyright (C) 2011  The IPython Development Team

      #

      #  Distributed under the terms of the BSD License.  The full license is in

      #  the file COPYING, distributed as part of this software.

      #-----------------------------------------------------------------------------

      #-----------------------------------------------------------------------------

      # Imports

      #-----------------------------------------------------------------------------

      def url_path_join(*pieces):

          """Join components of url into a relative url

          Use to prevent double slash when joining subpath. This will leave the

          initial and final / in place

          """

          initial = pieces[0].startswith('/')

          final = pieces[-1].endswith('/')

          striped = [s.strip('/') for s in pieces]

          result = '/'.join(s for s in striped if s)

          if initial: result = '/' + result

          if final: result = result + '/'

          if result == '//': result = '/'

          return result

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				"""Notebook related utilities

				Authors:

				* Brian Granger
				"""

				#-----------------------------------------------------------------------------
				# Copyright (C) 2011 The IPython Development Team
				#
				# Distributed under the terms of the BSD License. The full license is in
				# the file COPYING, distributed as part of this software.
				#-----------------------------------------------------------------------------

				#-----------------------------------------------------------------------------
				# Imports
				#-----------------------------------------------------------------------------

				def url_path_join(*pieces):
				"""Join components of url into a relative url

				Use to prevent double slash when joining subpath. This will leave the
				initial and final / in place
				"""
				initial = pieces[0].startswith('/')
				final = pieces[-1].endswith('/')
				striped = [s.strip('/') for s in pieces]
				result = '/'.join(s for s in striped if s)
				if initial: result = '/' + result
				if final: result = result + '/'
				if result == '//': result = '/'
				return result