##// END OF EJS Templates
deprecation warning on nbformat.current
deprecation warning on nbformat.current

File last commit:

r16160:71e9d6ea
r18608:f3b4b765
Show More
asyncresult.rst
150 lines | 5.1 KiB | text/x-rst | RstLexer

The AsyncResult object

In non-blocking mode, :meth:`apply` submits the command to be executed and then returns a :class:`~.AsyncResult` object immediately. The AsyncResult object gives you a way of getting a result at a later time through its :meth:`get` method, but it also collects metadata on execution.

Beyond multiprocessing's AsyncResult

Note

The :class:`~.AsyncResult` object provides a superset of the interface in :py:class:`multiprocessing.pool.AsyncResult`. See the official Python documentation for more on the basics of this interface.

Our AsyncResult objects add a number of convenient features for working with parallel results, beyond what is provided by the original AsyncResult.

get_dict

First, is :meth:`.AsyncResult.get_dict`, which pulls results as a dictionary keyed by engine_id, rather than a flat list. This is useful for quickly coordinating or distributing information about all of the engines.

As an example, here is a quick call that gives every engine a dict showing the PID of every other engine:

In [10]: ar = rc[:].apply_async(os.getpid)
In [11]: pids = ar.get_dict()
In [12]: rc[:]['pid_map'] = pids

This trick is particularly useful when setting up inter-engine communication, as in IPython's :file:`examples/parallel/interengine` examples.

Metadata

IPython.parallel tracks some metadata about the tasks, which is stored in the :attr:`.Client.metadata` dict. The AsyncResult object gives you an interface for this information as well, including timestamps stdout/err, and engine IDs.

Timing

IPython tracks various timestamps as :py:class:`.datetime` objects, and the AsyncResult object has a few properties that turn these into useful times (in seconds as floats).

For use while the tasks are still pending:

  • :attr:`ar.elapsed` is just the elapsed seconds since submission, for use before the AsyncResult is complete.

  • :attr:`ar.progress` is the number of tasks that have completed. Fractional progress would be:

    1.0 * ar.progress / len(ar)
    
  • :meth:`AsyncResult.wait_interactive` will wait for the result to finish, but print out status updates on progress and elapsed time while it waits.

For use after the tasks are done:

  • :attr:`ar.serial_time` is the sum of the computation time of all of the tasks done in parallel.
  • :attr:`ar.wall_time` is the time between the first task submitted and last result received. This is the actual cost of computation, including IPython overhead.

Note

wall_time is only precise if the Client is waiting for results when the task finished, because the received timestamp is made when the result is unpacked by the Client, triggered by the :meth:`~Client.spin` call. If you are doing work in the Client, and not waiting/spinning, then received might be artificially high.

An often interesting metric is the time it actually cost to do the work in parallel relative to the serial computation, and this can be given simply with

speedup = ar.serial_time / ar.wall_time

Map results are iterable!

When an AsyncResult object has multiple results (e.g. the :class:`~AsyncMapResult` object), you can actually iterate through results themselves, and act on them as they arrive:

That is to say, if you treat an AsyncMapResult as if it were a list of your actual results, it should behave as you would expect, with the only difference being that you can start iterating through the results before they have even been computed.

This lets you do a dumb version of map/reduce with the builtin Python functions, and the only difference between doing this locally and doing it remotely in parallel is using the asynchronous view.map instead of the builtin map.

Here is a simple one-line RMS (root-mean-square) implemented with Python's builtin map/reduce.

In [38]: X = np.linspace(0,100)

In [39]: from math import sqrt

In [40]: add = lambda a,b: a+b

In [41]: sq = lambda x: x*x

In [42]: sqrt(reduce(add, map(sq, X)) / len(X))
Out[42]: 58.028845747399714

In [43]: sqrt(reduce(add, view.map(sq, X)) / len(X))
Out[43]: 58.028845747399714

To break that down:

  1. map(sq, X) Compute the square of each element in the list (locally, or in parallel)
  2. reduce(add, sqX) / len(X) compute the mean by summing over the list (or AsyncMapResult) and dividing by the size
  3. take the square root of the resulting number