##// END OF EJS Templates
use cs get history instead of node.history, node history have to much reference calls
use cs get history instead of node.history, node history have to much reference calls

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__init__.py
67 lines | 2.1 KiB | text/x-python | PythonLexer
# -*- coding: utf-8 -*-
"""
rhodecode.lib.__init__
~~~~~~~~~~~~~~~~~~~~~~~
Some simple helper functions
:created_on: Jan 5, 2011
:author: marcink
:copyright: (C) 2009-2010 Marcin Kuzminski <marcin@python-works.com>
:license: GPLv3, see COPYING for more details.
"""
# This program is free software; you can redistribute it and/or
# modify it under the terms of the GNU General Public License
# as published by the Free Software Foundation; version 2
# of the License or (at your opinion) any later version of the license.
#
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU General Public License for more details.
#
# You should have received a copy of the GNU General Public License
# along with this program; if not, write to the Free Software
# Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston,
# MA 02110-1301, USA.
def str2bool(s):
if s is None:
return False
if s in (True, False):
return s
s = str(s).strip().lower()
return s in ('t', 'true', 'y', 'yes', 'on', '1')
def generate_api_key(username, salt=None):
"""
Generates uniq API key for given username
:param username: username as string
:param salt: salt to hash generate KEY
"""
from tempfile import _RandomNameSequence
import hashlib
if salt is None:
salt = _RandomNameSequence().next()
return hashlib.sha1(username + salt).hexdigest()
def safe_unicode(str):
"""
safe unicode function. In case of UnicodeDecode error we try to return
unicode with errors replace, if this fails we return unicode with
string_escape decoding
"""
try:
u_str = unicode(str)
except UnicodeDecodeError:
try:
u_str = unicode(str, 'utf-8', 'replace')
except UnicodeDecodeError:
#incase we have a decode error just represent as byte string
u_str = unicode(str(str).encode('string_escape'))
return u_str