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simplified str2bool, and moved safe_unicode out of helpers since it was not html specific function
simplified str2bool, and moved safe_unicode out of helpers since it was not html specific function

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__init__.py
67 lines | 2.1 KiB | text/x-python | PythonLexer
# -*- coding: utf-8 -*-
"""
rhodecode.lib.__init__
~~~~~~~~~~~~~~~~~~~~~~~
Some simple helper functions
:created_on: Jan 5, 2011
:author: marcink
:copyright: (C) 2009-2010 Marcin Kuzminski <marcin@python-works.com>
:license: GPLv3, see COPYING for more details.
"""
# This program is free software; you can redistribute it and/or
# modify it under the terms of the GNU General Public License
# as published by the Free Software Foundation; version 2
# of the License or (at your opinion) any later version of the license.
#
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU General Public License for more details.
#
# You should have received a copy of the GNU General Public License
# along with this program; if not, write to the Free Software
# Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston,
# MA 02110-1301, USA.
def str2bool(s):
if s is None:
return False
if s in (True, False):
return s
s = str(s).strip().lower()
return s in ('t', 'true', 'y', 'yes', 'on', '1')
def generate_api_key(username, salt=None):
"""
Generates uniq API key for given username
:param username: username as string
:param salt: salt to hash generate KEY
"""
from tempfile import _RandomNameSequence
import hashlib
if salt is None:
salt = _RandomNameSequence().next()
return hashlib.sha1(username + salt).hexdigest()
def safe_unicode(str):
"""
safe unicode function. In case of UnicodeDecode error we try to return
unicode with errors replace, if this fails we return unicode with
string_escape decoding
"""
try:
u_str = unicode(str)
except UnicodeDecodeError:
try:
u_str = unicode(str, 'utf-8', 'replace')
except UnicodeDecodeError:
#incase we have a decode error just represent as byte string
u_str = unicode(str(str).encode('string_escape'))
return u_str