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security bugfix simplehg wasn't checking for permissions on remote commands different than pull or push.
security bugfix simplehg wasn't checking for permissions on remote commands different than pull or push.

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test_settings.py
55 lines | 2.0 KiB | text/x-python | PythonLexer
from rhodecode.model.db import Repository
from rhodecode.tests import *
class TestSettingsController(TestController):
def test_index(self):
self.log_user()
response = self.app.get(url(controller='settings', action='index',
repo_name='vcs_test'))
# Test response...
def test_fork(self):
self.log_user()
response = self.app.get(url(controller='settings', action='fork',
repo_name='vcs_test'))
def test_fork_create(self):
self.log_user()
fork_name = 'vcs_test_fork'
description = 'fork of vcs test'
repo_name = 'vcs_test'
response = self.app.post(url(controller='settings', action='fork_create',
repo_name=repo_name),
{'fork_name':fork_name,
'description':description,
'private':'False'})
print response
#test if we have a message that fork is ok
assert 'fork %s repository as %s task added' \
% (repo_name, fork_name) in response.session['flash'][0], 'No flash message about fork'
#test if the fork was created in the database
fork_repo = self.sa.query(Repository).filter(Repository.repo_name == fork_name).one()
assert fork_repo.repo_name == fork_name, 'wrong name of repo name in new db fork repo'
assert fork_repo.fork.repo_name == repo_name, 'wrong fork parrent'
#test if fork is visible in the list ?
response = response.follow()
#check if fork is marked as fork
response = self.app.get(url(controller='summary', action='index',
repo_name=fork_name))
print response
assert 'Fork of %s' % repo_name in response.body, 'no message about that this repo is a fork'