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bdiff.py
76 lines | 2.0 KiB | text/x-python | PythonLexer
Martin Geisler
pure Python implementation of bdiff.c
r7703 # bdiff.py - Python implementation of bdiff.c
#
# Copyright 2009 Matt Mackall <mpm@selenic.com> and others
#
Martin Geisler
updated license to be explicit about GPL version 2
r8225 # This software may be used and distributed according to the terms of the
Matt Mackall
Update license to GPLv2+
r10263 # GNU General Public License version 2 or any later version.
Martin Geisler
pure Python implementation of bdiff.c
r7703
import struct, difflib
Matt Mackall
pure/bdiff: fix circular import
r7944
def splitnewlines(text):
'''like str.splitlines, but only split on newlines.'''
lines = [l + '\n' for l in text.split('\n')]
if lines:
if lines[-1] == '\n':
lines.pop()
else:
lines[-1] = lines[-1][:-1]
return lines
Martin Geisler
pure Python implementation of bdiff.c
r7703
def _normalizeblocks(a, b, blocks):
prev = None
for curr in blocks:
if prev is None:
prev = curr
continue
shift = 0
a1, b1, l1 = prev
a1end = a1 + l1
b1end = b1 + l1
a2, b2, l2 = curr
a2end = a2 + l2
b2end = b2 + l2
if a1end == a2:
while a1end+shift < a2end and a[a1end+shift] == b[b1end+shift]:
shift += 1
elif b1end == b2:
while b1end+shift < b2end and a[a1end+shift] == b[b1end+shift]:
shift += 1
yield a1, b1, l1+shift
prev = a2+shift, b2+shift, l2-shift
yield prev
def bdiff(a, b):
a = str(a).splitlines(True)
b = str(b).splitlines(True)
if not a:
s = "".join(b)
return s and (struct.pack(">lll", 0, 0, len(s)) + s)
bin = []
p = [0]
for i in a: p.append(p[-1] + len(i))
d = difflib.SequenceMatcher(None, a, b).get_matching_blocks()
d = _normalizeblocks(a, b, d)
la = 0
lb = 0
for am, bm, size in d:
s = "".join(b[lb:bm])
if am > la or s:
bin.append(struct.pack(">lll", p[la], p[am], len(s)) + s)
la = am + size
lb = bm + size
return "".join(bin)
def blocks(a, b):
Matt Mackall
pure/bdiff: fix circular import
r7944 an = splitnewlines(a)
bn = splitnewlines(b)
Martin Geisler
pure Python implementation of bdiff.c
r7703 d = difflib.SequenceMatcher(None, an, bn).get_matching_blocks()
d = _normalizeblocks(an, bn, d)
return [(i, i + n, j, j + n) for (i, j, n) in d]