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dicthelpers.py
55 lines | 1.6 KiB | text/x-python | PythonLexer
Siddharth Agarwal
mercurial: implement diff and join for dicts...
r18820 # dicthelpers.py - helper routines for Python dicts
#
# Copyright 2013 Facebook
#
# This software may be used and distributed according to the terms of the
# GNU General Public License version 2 or any later version.
Siddharth Agarwal
dicthelpers: inline diff and join code...
r18847 def diff(d1, d2, default=None):
'''Return all key-value pairs that are different between d1 and d2.
This includes keys that are present in one dict but not the other, and
keys whose values are different. The return value is a dict with values
being pairs of values from d1 and d2 respectively, and missing values
Siddharth Agarwal
dicthelpers.diff: compare against default for missing values...
r18894 treated as default, so if a value is missing from one dict and the same as
default in the other, it will not be returned.'''
Siddharth Agarwal
mercurial: implement diff and join for dicts...
r18820 res = {}
Siddharth Agarwal
dicthelpers: inline diff and join code...
r18847 if d1 is d2:
Siddharth Agarwal
mercurial: implement diff and join for dicts...
r18820 # same dict, so diff is empty
return res
for k1, v1 in d1.iteritems():
Siddharth Agarwal
dicthelpers.diff: compare against default for missing values...
r18894 v2 = d2.get(k1, default)
if v1 != v2:
res[k1] = (v1, v2)
Siddharth Agarwal
mercurial: implement diff and join for dicts...
r18820
Siddharth Agarwal
dicthelpers: inline diff and join code...
r18847 for k2 in d2:
if k2 not in d1:
Siddharth Agarwal
dicthelpers.diff: compare against default for missing values...
r18894 v2 = d2[k2]
if v2 != default:
res[k2] = (default, v2)
Siddharth Agarwal
dicthelpers: inline diff and join code...
r18847
return res
def join(d1, d2, default=None):
'''Return all key-value pairs from both d1 and d2.
This is akin to an outer join in relational algebra. The return value is a
dict with values being pairs of values from d1 and d2 respectively, and
missing values represented as default.'''
res = {}
for k1, v1 in d1.iteritems():
if k1 in d2:
res[k1] = (v1, d2[k1])
else:
res[k1] = (v1, default)
Siddharth Agarwal
mercurial: implement diff and join for dicts...
r18820 if d1 is d2:
return res
for k2 in d2:
if k2 not in d1:
res[k2] = (default, d2[k2])
return res