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templater: clean up the process method, separating code paths
templater: clean up the process method, separating code paths

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r8225:46293a0c default
r8474:bccc90b5 default
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base85.py
74 lines | 1.9 KiB | text/x-python | PythonLexer
Brendan Cully
Pure python base85 fallback...
r7701 # base85.py: pure python base85 codec
#
# Copyright (C) 2009 Brendan Cully <brendan@kublai.com>
#
Martin Geisler
updated license to be explicit about GPL version 2
r8225 # This software may be used and distributed according to the terms of the
# GNU General Public License version 2, incorporated herein by reference.
Brendan Cully
Pure python base85 fallback...
r7701
import struct
_b85chars = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ" \
"abcdefghijklmnopqrstuvwxyz!#$%&()*+-;<=>?@^_`{|}~"
Mads Kiilerich
Optimization of pure.base85.b85encode...
r7835 _b85chars2 = [(a + b) for a in _b85chars for b in _b85chars]
Brendan Cully
Pure python base85 fallback...
r7701 _b85dec = {}
def _mkb85dec():
for i in range(len(_b85chars)):
_b85dec[_b85chars[i]] = i
def b85encode(text, pad=False):
"""encode text in base85 format"""
l = len(text)
r = l % 4
if r:
text += '\0' * (4 - r)
longs = len(text) >> 2
words = struct.unpack('>%dL' % (longs), text)
Dirkjan Ochtman
kill another trailing space
r7881 out = ''.join(_b85chars[(word / 52200625) % 85] +
Mads Kiilerich
Optimization of pure.base85.b85encode...
r7835 _b85chars2[(word / 7225) % 7225] +
_b85chars2[word % 7225]
for word in words)
Brendan Cully
Pure python base85 fallback...
r7701
if pad:
return out
# Trim padding
olen = l % 4
if olen:
olen += 1
olen += l / 4 * 5
return out[:olen]
def b85decode(text):
"""decode base85-encoded text"""
if not _b85dec:
_mkb85dec()
l = len(text)
out = []
for i in range(0, len(text), 5):
chunk = text[i:i+5]
acc = 0
for j in range(len(chunk)):
try:
acc = acc * 85 + _b85dec[chunk[j]]
except KeyError:
raise TypeError('Bad base85 character at byte %d' % (i + j))
if acc > 4294967295:
raise OverflowError('Base85 overflow in hunk starting at byte %d' % i)
out.append(acc)
# Pad final chunk if necessary
cl = l % 5
if cl:
acc *= 85 ** (5 - cl)
if cl > 1:
acc += 0xffffff >> (cl - 2) * 8
out[-1] = acc
out = struct.pack('>%dL' % (len(out)), *out)
if cl:
out = out[:-(5 - cl)]
return out