# HG changeset patch # User Alexis S. L. Carvalho # Date 2006-10-12 17:04:11 # Node ID 4bad632913d8a2281fca44b2b3f7d454a72838ce # Parent 751df21dad72564ff09614b9f4d23df6ff4d4f6e python2.5 PyArg_ParseTuple fix Python 2.5 doesn't like it when we mix str objects and the "t#" format in PyArg_ParseTuple. Change it to use "s#". Tested with python 2.3, 2.4 and 2.5. diff --git a/mercurial/base85.c b/mercurial/base85.c --- a/mercurial/base85.c +++ b/mercurial/base85.c @@ -35,7 +35,7 @@ b85encode(PyObject *self, PyObject *args unsigned int acc, val, ch; int pad = 0; - if (!PyArg_ParseTuple(args, "t#|i", &text, &len, &pad)) + if (!PyArg_ParseTuple(args, "s#|i", &text, &len, &pad)) return NULL; if (pad) @@ -82,7 +82,7 @@ b85decode(PyObject *self, PyObject *args int len, i, j, olen, c, cap; unsigned int acc; - if (!PyArg_ParseTuple(args, "t#", &text, &len)) + if (!PyArg_ParseTuple(args, "s#", &text, &len)) return NULL; olen = len / 5 * 4; diff --git a/mercurial/bdiff.c b/mercurial/bdiff.c --- a/mercurial/bdiff.c +++ b/mercurial/bdiff.c @@ -308,7 +308,7 @@ static PyObject *bdiff(PyObject *self, P char encode[12], *rb; int an, bn, len = 0, la, lb; - if (!PyArg_ParseTuple(args, "t#t#:bdiff", &sa, &la, &sb, &lb)) + if (!PyArg_ParseTuple(args, "s#s#:bdiff", &sa, &la, &sb, &lb)) return NULL; an = splitlines(sa, la, &al);