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backout: use commonancestorsheads for checking linear heritage If two revisions are linearly related, there will only be one ancestor, and commonancestors and commonancestorsheads would give the same result. commonancestorsheads is however slightly simpler, faster and more correct.

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scmwindows.py
46 lines | 1.6 KiB | text/x-python | PythonLexer
import os
import osutil
import util
import _winreg
def systemrcpath():
'''return default os-specific hgrc search path'''
rcpath = []
filename = util.executablepath()
# Use mercurial.ini found in directory with hg.exe
progrc = os.path.join(os.path.dirname(filename), 'mercurial.ini')
if os.path.isfile(progrc):
rcpath.append(progrc)
return rcpath
# Use hgrc.d found in directory with hg.exe
progrcd = os.path.join(os.path.dirname(filename), 'hgrc.d')
if os.path.isdir(progrcd):
for f, kind in osutil.listdir(progrcd):
if f.endswith('.rc'):
rcpath.append(os.path.join(progrcd, f))
return rcpath
# else look for a system rcpath in the registry
value = util.lookupreg('SOFTWARE\\Mercurial', None,
_winreg.HKEY_LOCAL_MACHINE)
if not isinstance(value, str) or not value:
return rcpath
value = util.localpath(value)
for p in value.split(os.pathsep):
if p.lower().endswith('mercurial.ini'):
rcpath.append(p)
elif os.path.isdir(p):
for f, kind in osutil.listdir(p):
if f.endswith('.rc'):
rcpath.append(os.path.join(p, f))
return rcpath
def userrcpath():
'''return os-specific hgrc search path to the user dir'''
home = os.path.expanduser('~')
path = [os.path.join(home, 'mercurial.ini'),
os.path.join(home, '.hgrc')]
userprofile = os.environ.get('USERPROFILE')
if userprofile:
path.append(os.path.join(userprofile, 'mercurial.ini'))
path.append(os.path.join(userprofile, '.hgrc'))
return path