##// END OF EJS Templates
patch: propagate eolmode down to patchfile...
patch: propagate eolmode down to patchfile The old code mapped the value of eolmode ('strict', 'crlf' or 'lf') to eol (None, '\r\n' or '\n') at the entry point in internalpatch. The value of eol was then used directly as the desired EOL in patchfile. We now delay the mapping and let patchfile do it instead. This allows for more complicated behavior where it does not make sense to map eolmode directly to the target EOLs.

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ancestor.py
86 lines | 2.4 KiB | text/x-python | PythonLexer
# ancestor.py - generic DAG ancestor algorithm for mercurial
#
# Copyright 2006 Matt Mackall <mpm@selenic.com>
#
# This software may be used and distributed according to the terms of the
# GNU General Public License version 2, incorporated herein by reference.
import heapq
def ancestor(a, b, pfunc):
"""
return a minimal-distance ancestor of nodes a and b, or None if there is no
such ancestor. Note that there can be several ancestors with the same
(minimal) distance, and the one returned is arbitrary.
pfunc must return a list of parent vertices for a given vertex
"""
if a == b:
return a
# find depth from root of all ancestors
parentcache = {}
visit = [a, b]
depth = {}
while visit:
vertex = visit[-1]
pl = pfunc(vertex)
parentcache[vertex] = pl
if not pl:
depth[vertex] = 0
visit.pop()
else:
for p in pl:
if p == a or p == b: # did we find a or b as a parent?
return p # we're done
if p not in depth:
visit.append(p)
if visit[-1] == vertex:
depth[vertex] = min([depth[p] for p in pl]) - 1
visit.pop()
# traverse ancestors in order of decreasing distance from root
def ancestors(vertex):
h = [(depth[vertex], vertex)]
seen = set()
while h:
d, n = heapq.heappop(h)
if n not in seen:
seen.add(n)
yield (d, n)
for p in parentcache[n]:
heapq.heappush(h, (depth[p], p))
def generations(vertex):
sg, s = None, set()
for g, v in ancestors(vertex):
if g != sg:
if sg:
yield sg, s
sg, s = g, set((v,))
else:
s.add(v)
yield sg, s
x = generations(a)
y = generations(b)
gx = x.next()
gy = y.next()
# increment each ancestor list until it is closer to root than
# the other, or they match
try:
while 1:
if gx[0] == gy[0]:
for v in gx[1]:
if v in gy[1]:
return v
gy = y.next()
gx = x.next()
elif gx[0] > gy[0]:
gy = y.next()
else:
gx = x.next()
except StopIteration:
return None