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sslutil: print a warning when using TLS 1.0 on legacy Python...
sslutil: print a warning when using TLS 1.0 on legacy Python Mercurial now requires TLS 1.1+ when TLS 1.1+ is supported by the client. Since we made the decision to require TLS 1.1+ when running with modern Python versions, it makes sense to do something for legacy Python versions that only support TLS 1.0. Feature parity would be to prevent TLS 1.0 connections out of the box and require a config option to enable them. However, this is extremely user hostile since Mercurial wouldn't talk to https:// by default in these installations! I can easily see how someone would do something foolish like use "--insecure" instead - and that would be worse than allowing TLS 1.0! This patch takes the compromise position of printing a warning when performing TLS 1.0 connections when running on old Python versions. While this warning is no more annoying than the CA certificate / fingerprint warnings in Mercurial 3.8, we provide a config option to disable the warning because to many people upgrading Python to make the warning go away is not an available recourse (unlike pinning fingerprints is for the CA warning). The warning appears as optional output in a lot of tests.

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bdiff.py
98 lines | 2.5 KiB | text/x-python | PythonLexer
# bdiff.py - Python implementation of bdiff.c
#
# Copyright 2009 Matt Mackall <mpm@selenic.com> and others
#
# This software may be used and distributed according to the terms of the
# GNU General Public License version 2 or any later version.
from __future__ import absolute_import
import array
import difflib
import re
import struct
def splitnewlines(text):
'''like str.splitlines, but only split on newlines.'''
lines = [l + '\n' for l in text.split('\n')]
if lines:
if lines[-1] == '\n':
lines.pop()
else:
lines[-1] = lines[-1][:-1]
return lines
def _normalizeblocks(a, b, blocks):
prev = None
r = []
for curr in blocks:
if prev is None:
prev = curr
continue
shift = 0
a1, b1, l1 = prev
a1end = a1 + l1
b1end = b1 + l1
a2, b2, l2 = curr
a2end = a2 + l2
b2end = b2 + l2
if a1end == a2:
while (a1end + shift < a2end and
a[a1end + shift] == b[b1end + shift]):
shift += 1
elif b1end == b2:
while (b1end + shift < b2end and
a[a1end + shift] == b[b1end + shift]):
shift += 1
r.append((a1, b1, l1 + shift))
prev = a2 + shift, b2 + shift, l2 - shift
r.append(prev)
return r
def _tostring(c):
if type(c) is array.array:
# this copy overhead isn't ideal
return c.tostring()
return str(c)
def bdiff(a, b):
a = _tostring(a).splitlines(True)
b = _tostring(b).splitlines(True)
if not a:
s = "".join(b)
return s and (struct.pack(">lll", 0, 0, len(s)) + s)
bin = []
p = [0]
for i in a: p.append(p[-1] + len(i))
d = difflib.SequenceMatcher(None, a, b).get_matching_blocks()
d = _normalizeblocks(a, b, d)
la = 0
lb = 0
for am, bm, size in d:
s = "".join(b[lb:bm])
if am > la or s:
bin.append(struct.pack(">lll", p[la], p[am], len(s)) + s)
la = am + size
lb = bm + size
return "".join(bin)
def blocks(a, b):
an = splitnewlines(a)
bn = splitnewlines(b)
d = difflib.SequenceMatcher(None, an, bn).get_matching_blocks()
d = _normalizeblocks(an, bn, d)
return [(i, i + n, j, j + n) for (i, j, n) in d]
def fixws(text, allws):
if allws:
text = re.sub('[ \t\r]+', '', text)
else:
text = re.sub('[ \t\r]+', ' ', text)
text = text.replace(' \n', '\n')
return text