upstream/mercurial-mirror Files · mercurial/dicthelpers.py

shelve: use rebase instead of merge (issue4068)...

shelve: use rebase instead of merge (issue4068) Previously, shelve used merge to unshelve things. This meant that if you shelved changes on one branch, then unshelved on another, all the changes from the first branch would be present in the second branch, and not just the shelved changes. The fix is to use rebase to pick the shelve commit off the original branch and place it on top of the new branch. This means only the shelved changes are brought across. This has the side effect of fixing several other issues in shelve: - you can now unshelve into a file that already has pending changes - unshelve a mv/cp now has the correct dirstate value (A instead of M) - you can now unshelve to an ancestor of the shelve - unshelve now no longer deletes untracked .orig files Updates tests and adds a new one to cover the issue. The test changes fall into a few categories: - I removed some excess output - The --continue/--abort state is a little different, so the parents and dirstate needed updating - Removed some untracked files at certain points that cluttered the output

Siddharth Agarwal - - Load All Authors

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      # dicthelpers.py - helper routines for Python dicts

      #

      # Copyright 2013 Facebook

      #

      # This software may be used and distributed according to the terms of the

      # GNU General Public License version 2 or any later version.

      def diff(d1, d2, default=None):

          '''Return all key-value pairs that are different between d1 and d2.

          This includes keys that are present in one dict but not the other, and

          keys whose values are different. The return value is a dict with values

          being pairs of values from d1 and d2 respectively, and missing values

          treated as default, so if a value is missing from one dict and the same as

          default in the other, it will not be returned.'''

          res = {}

          if d1 is d2:

              # same dict, so diff is empty

              return res

          for k1, v1 in d1.iteritems():

              v2 = d2.get(k1, default)

              if v1 != v2:

                  res[k1] = (v1, v2)

          for k2 in d2:

              if k2 not in d1:

                  v2 = d2[k2]

                  if v2 != default:

                      res[k2] = (default, v2)

          return res

      def join(d1, d2, default=None):

          '''Return all key-value pairs from both d1 and d2.

          This is akin to an outer join in relational algebra. The return value is a

          dict with values being pairs of values from d1 and d2 respectively, and

          missing values represented as default.'''

          res = {}

          for k1, v1 in d1.iteritems():

              if k1 in d2:

                  res[k1] = (v1, d2[k1])

              else:

                  res[k1] = (v1, default)

          if d1 is d2:

              return res

          for k2 in d2:

              if k2 not in d1:

                  res[k2] = (default, d2[k2])

          return res

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				# dicthelpers.py - helper routines for Python dicts
				#
				# Copyright 2013 Facebook
				#
				# This software may be used and distributed according to the terms of the
				# GNU General Public License version 2 or any later version.

				def diff(d1, d2, default=None):
				'''Return all key-value pairs that are different between d1 and d2.

				This includes keys that are present in one dict but not the other, and
				keys whose values are different. The return value is a dict with values
				being pairs of values from d1 and d2 respectively, and missing values
				treated as default, so if a value is missing from one dict and the same as
				default in the other, it will not be returned.'''
				res = {}
				if d1 is d2:
				# same dict, so diff is empty
				return res

				for k1, v1 in d1.iteritems():
				v2 = d2.get(k1, default)
				if v1 != v2:
				res[k1] = (v1, v2)

				for k2 in d2:
				if k2 not in d1:
				v2 = d2[k2]
				if v2 != default:
				res[k2] = (default, v2)

				return res

				def join(d1, d2, default=None):
				'''Return all key-value pairs from both d1 and d2.

				This is akin to an outer join in relational algebra. The return value is a
				dict with values being pairs of values from d1 and d2 respectively, and
				missing values represented as default.'''
				res = {}

				for k1, v1 in d1.iteritems():
				if k1 in d2:
				res[k1] = (v1, d2[k1])
				else:
				res[k1] = (v1, default)

				if d1 is d2:
				return res

				for k2 in d2:
				if k2 not in d1:
				res[k2] = (default, d2[k2])

				return res