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Reduce string duplication in compression code...
Reduce string duplication in compression code This cuts down on string copies and allows buffers (instead of strings) to be passed into the compression code

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filelog.py
107 lines | 3.3 KiB | text/x-python | PythonLexer
# filelog.py - file history class for mercurial
#
# Copyright 2005 Matt Mackall <mpm@selenic.com>
#
# This software may be used and distributed according to the terms
# of the GNU General Public License, incorporated herein by reference.
import os
from revlog import *
from demandload import *
demandload(globals(), "bdiff")
class filelog(revlog):
def __init__(self, opener, path):
revlog.__init__(self, opener,
os.path.join("data", self.encodedir(path + ".i")),
os.path.join("data", self.encodedir(path + ".d")))
# This avoids a collision between a file named foo and a dir named
# foo.i or foo.d
def encodedir(self, path):
return (path
.replace(".hg/", ".hg.hg/")
.replace(".i/", ".i.hg/")
.replace(".d/", ".d.hg/"))
def decodedir(self, path):
return (path
.replace(".d.hg/", ".d/")
.replace(".i.hg/", ".i/")
.replace(".hg.hg/", ".hg/"))
def read(self, node):
t = self.revision(node)
if not t.startswith('\1\n'):
return t
s = t.find('\1\n', 2)
return t[s+2:]
def readmeta(self, node):
t = self.revision(node)
if not t.startswith('\1\n'):
return {}
s = t.find('\1\n', 2)
mt = t[2:s]
m = {}
for l in mt.splitlines():
k, v = l.split(": ", 1)
m[k] = v
return m
def add(self, text, meta, transaction, link, p1=None, p2=None):
if meta or text.startswith('\1\n'):
mt = ""
if meta:
mt = [ "%s: %s\n" % (k, v) for k,v in meta.items() ]
text = "\1\n" + "".join(mt) + "\1\n" + text
return self.addrevision(text, transaction, link, p1, p2)
def renamed(self, node):
if 0 and self.parents(node)[0] != nullid:
return False
m = self.readmeta(node)
if m and m.has_key("copy"):
return (m["copy"], bin(m["copyrev"]))
return False
def annotate(self, node):
def decorate(text, rev):
return ([rev] * len(text.splitlines()), text)
def pair(parent, child):
for a1, a2, b1, b2 in bdiff.blocks(parent[1], child[1]):
child[0][b1:b2] = parent[0][a1:a2]
return child
# find all ancestors
needed = {node:1}
visit = [node]
while visit:
n = visit.pop(0)
for p in self.parents(n):
if p not in needed:
needed[p] = 1
visit.append(p)
else:
# count how many times we'll use this
needed[p] += 1
# sort by revision which is a topological order
visit = [ (self.rev(n), n) for n in needed.keys() ]
visit.sort()
hist = {}
for r,n in visit:
curr = decorate(self.read(n), self.linkrev(n))
for p in self.parents(n):
if p != nullid:
curr = pair(hist[p], curr)
# trim the history of unneeded revs
needed[p] -= 1
if not needed[p]:
del hist[p]
hist[n] = curr
return zip(hist[n][0], hist[n][1].splitlines(1))