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namespaces: record and expose whether namespace is built-in...
namespaces: record and expose whether namespace is built-in Currently, the templating layer tends to treat each namespace as a one-off, with explicit usage of {bookmarks}, {tags}, {branch}, etc instead of using {namespaces}. It would be really useful if we could iterate over namespaces and operate on them generically. However, some consumers may wish to differentiate namespaces by whether they are built-in to core Mercurial or provided by extensions. Expected use cases include ignoring non-built-in namespaces or emitting a generic label for non-built-in namespaces. This commit introduces an attribute on namespace instances that says whether the namespace is "built-in" and then exposes this to the templating layer. As part of this, we implement a reusable extension for defining custom names on each changeset for testing. A second consumer will be introduced in a subsequent commit.
Yuya Nishihara - - Load All Authors

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test-glog-topological.t
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This test file aims at test topological iteration and the various configuration it can has.
$ cat >> $HGRCPATH << EOF
> [ui]
> logtemplate={rev}\n
> EOF
On this simple example, all topological branch are displayed in turn until we
can finally display 0. this implies skipping from 8 to 3 and coming back to 7
later.
$ hg init test01
$ cd test01
$ hg unbundle $TESTDIR/bundles/remote.hg
adding changesets
adding manifests
adding file changes
added 9 changesets with 7 changes to 4 files (+1 heads)
(run 'hg heads' to see heads, 'hg merge' to merge)
$ hg log -G
o 8
|
| o 7
| |
| o 6
| |
| o 5
| |
| o 4
| |
o | 3
| |
o | 2
| |
o | 1
|/
o 0
(display all nodes)
$ hg log -G -r 'sort(all(), topo)'
o 8
|
o 3
|
o 2
|
o 1
|
| o 7
| |
| o 6
| |
| o 5
| |
| o 4
|/
o 0
(display nodes filtered by log options)
$ hg log -G -r 'sort(all(), topo)' -k '.3'
o 8
|
o 3
|
~
o 7
|
o 6
|
~
(revset skipping nodes)
$ hg log -G --rev 'sort(not (2+6), topo)'
o 8
|
o 3
:
o 1
|
| o 7
| :
| o 5
| |
| o 4
|/
o 0
(begin) from the other branch
$ hg log -G -r 'sort(all(), topo, topo.firstbranch=5)'
o 7
|
o 6
|
o 5
|
o 4
|
| o 8
| |
| o 3
| |
| o 2
| |
| o 1
|/
o 0