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# tagmerge.py - merge .hgtags files
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#
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# Copyright 2014 Angel Ezquerra <angel.ezquerra@gmail.com>
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#
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# This software may be used and distributed according to the terms of the
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# GNU General Public License version 2 or any later version.
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# This module implements an automatic merge algorithm for mercurial's tag files
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#
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# The tagmerge algorithm implemented in this module is able to resolve most
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# merge conflicts that currently would trigger a .hgtags merge conflict. The
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# only case that it does not (and cannot) handle is that in which two tags point
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# to different revisions on each merge parent _and_ their corresponding tag
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# histories have the same rank (i.e. the same length). In all other cases the
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# merge algorithm will choose the revision belonging to the parent with the
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# highest ranked tag history. The merged tag history is the combination of both
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# tag histories (special care is taken to try to combine common tag histories
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# where possible).
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#
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# In addition to actually merging the tags from two parents, taking into
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# account the base, the algorithm also tries to minimize the difference
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# between the merged tag file and the first parent's tag file (i.e. it tries to
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# make the merged tag order as as similar as possible to the first parent's tag
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# file order).
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#
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# The algorithm works as follows:
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# 1. read the tags from p1, p2 and the base
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# - when reading the p1 tags, also get the line numbers associated to each
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# tag node (these will be used to sort the merged tags in a way that
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# minimizes the diff to p1). Ignore the file numbers when reading p2 and
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# the base
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# 2. recover the "lost tags" (i.e. those that are found in the base but not on
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# p1 or p2) and add them back to p1 and/or p2
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# - at this point the only tags that are on p1 but not on p2 are those new
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# tags that were introduced in p1. Same thing for the tags that are on p2
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# but not on p2
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# 3. take all tags that are only on p1 or only on p2 (but not on the base)
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# - Note that these are the tags that were introduced between base and p1
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# and between base and p2, possibly on separate clones
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# 4. for each tag found both on p1 and p2 perform the following merge algorithm:
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# - the tags conflict if their tag "histories" have the same "rank" (i.e.
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# length) AND the last (current) tag is NOT the same
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# - for non conflicting tags:
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# - choose which are the high and the low ranking nodes
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# - the high ranking list of nodes is the one that is longer.
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# In case of draw favor p1
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# - the merged node list is made of 3 parts:
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# - first the nodes that are common to the beginning of both
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# the low and the high ranking nodes
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# - second the non common low ranking nodes
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# - finally the non common high ranking nodes (with the last
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# one being the merged tag node)
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# - note that this is equivalent to putting the whole low ranking
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# node list first, followed by the non common high ranking nodes
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# - note that during the merge we keep the "node line numbers", which will
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# be used when writing the merged tags to the tag file
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# 5. write the merged tags taking into account to their positions in the first
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# parent (i.e. try to keep the relative ordering of the nodes that come
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# from p1). This minimizes the diff between the merged and the p1 tag files
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# This is done by using the following algorithm
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# - group the nodes for a given tag that must be written next to each other
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# - A: nodes that come from consecutive lines on p1
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# - B: nodes that come from p2 (i.e. whose associated line number is
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# None) and are next to one of the a nodes in A
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# - each group is associated with a line number coming from p1
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# - generate a "tag block" for each of the groups
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# - a tag block is a set of consecutive "node tag" lines belonging to
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# the same tag and which will be written next to each other on the
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# merged tags file
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# - sort the "tag blocks" according to their associated number line
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# - put blocks whose nodes come all from p2 first
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# - write the tag blocks in the sorted order
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from __future__ import absolute_import
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from .i18n import _
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from .node import (
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hex,
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nullid,
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)
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from . import (
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tags as tagsmod,
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util,
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)
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hexnullid = hex(nullid)
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def readtagsformerge(ui, repo, lines, fn=b'', keeplinenums=False):
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'''read the .hgtags file into a structure that is suitable for merging
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Depending on the keeplinenums flag, clear the line numbers associated
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with each tag. This is done because only the line numbers of the first
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parent are useful for merging.
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'''
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filetags = tagsmod._readtaghist(
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ui, repo, lines, fn=fn, recode=None, calcnodelines=True
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)[1]
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for tagname, taginfo in filetags.items():
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if not keeplinenums:
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for el in taginfo:
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el[1] = None
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return filetags
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def grouptagnodesbyline(tagnodes):
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'''
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Group nearby nodes (i.e. those that must be written next to each other)
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The input is a list of [node, position] pairs, corresponding to a given tag
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The position is the line number where the node was found on the first parent
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.hgtags file, or None for those nodes that came from the base or the second
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parent .hgtags files.
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This function groups those [node, position] pairs, returning a list of
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groups of nodes that must be written next to each other because their
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positions are consecutive or have no position preference (because their
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position is None).
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The result is a list of [position, [consecutive node list]]
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'''
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firstlinenum = None
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for hexnode, linenum in tagnodes:
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firstlinenum = linenum
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if firstlinenum is not None:
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break
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if firstlinenum is None:
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return [[None, [el[0] for el in tagnodes]]]
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tagnodes[0][1] = firstlinenum
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groupednodes = [[firstlinenum, []]]
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prevlinenum = firstlinenum
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for hexnode, linenum in tagnodes:
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if linenum is not None and linenum - prevlinenum > 1:
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groupednodes.append([linenum, []])
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groupednodes[-1][1].append(hexnode)
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if linenum is not None:
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prevlinenum = linenum
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return groupednodes
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def writemergedtags(fcd, mergedtags):
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'''
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write the merged tags while trying to minimize the diff to the first parent
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This function uses the ordering info stored on the merged tags dict to
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generate an .hgtags file which is correct (in the sense that its contents
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correspond to the result of the tag merge) while also being as close as
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possible to the first parent's .hgtags file.
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'''
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# group the node-tag pairs that must be written next to each other
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for tname, taglist in list(mergedtags.items()):
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mergedtags[tname] = grouptagnodesbyline(taglist)
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# convert the grouped merged tags dict into a format that resembles the
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# final .hgtags file (i.e. a list of blocks of 'node tag' pairs)
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def taglist2string(tlist, tname):
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return b'\n'.join([b'%s %s' % (hexnode, tname) for hexnode in tlist])
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finaltags = []
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for tname, tags in mergedtags.items():
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for block in tags:
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block[1] = taglist2string(block[1], tname)
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finaltags += tags
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# the tag groups are linked to a "position" that can be used to sort them
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# before writing them
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# the position is calculated to ensure that the diff of the merged .hgtags
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# file to the first parent's .hgtags file is as small as possible
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finaltags.sort(key=lambda x: -1 if x[0] is None else x[0])
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# finally we can join the sorted groups to get the final contents of the
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# merged .hgtags file, and then write it to disk
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mergedtagstring = b'\n'.join([tags for rank, tags in finaltags if tags])
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fcd.write(mergedtagstring + b'\n', fcd.flags())
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def singletagmerge(p1nodes, p2nodes):
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'''
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merge the nodes corresponding to a single tag
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Note that the inputs are lists of node-linenum pairs (i.e. not just lists
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of nodes)
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'''
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if not p2nodes:
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return p1nodes
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if not p1nodes:
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return p2nodes
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# there is no conflict unless both tags point to different revisions
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# and have a non identical tag history
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p1currentnode = p1nodes[-1][0]
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p2currentnode = p2nodes[-1][0]
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if p1currentnode != p2currentnode and len(p1nodes) == len(p2nodes):
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# cannot merge two tags with same rank pointing to different nodes
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return None
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# which are the highest ranking (hr) / lowest ranking (lr) nodes?
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if len(p1nodes) >= len(p2nodes):
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hrnodes, lrnodes = p1nodes, p2nodes
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else:
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hrnodes, lrnodes = p2nodes, p1nodes
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# the lowest ranking nodes will be written first, followed by the highest
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# ranking nodes
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# to avoid unwanted tag rank explosion we try to see if there are some
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# common nodes that can be written only once
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commonidx = len(lrnodes)
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for n in range(len(lrnodes)):
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if hrnodes[n][0] != lrnodes[n][0]:
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commonidx = n
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break
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lrnodes[n][1] = p1nodes[n][1]
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# the merged node list has 3 parts:
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# - common nodes
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# - non common lowest ranking nodes
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# - non common highest ranking nodes
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# note that the common nodes plus the non common lowest ranking nodes is the
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# whole list of lr nodes
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return lrnodes + hrnodes[commonidx:]
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def merge(repo, fcd, fco, fca):
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'''
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Merge the tags of two revisions, taking into account the base tags
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Try to minimize the diff between the merged tags and the first parent tags
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'''
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ui = repo.ui
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# read the p1, p2 and base tags
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# only keep the line numbers for the p1 tags
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p1tags = readtagsformerge(
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ui, repo, fcd.data().splitlines(), fn=b"p1 tags", keeplinenums=True
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)
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p2tags = readtagsformerge(
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ui, repo, fco.data().splitlines(), fn=b"p2 tags", keeplinenums=False
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)
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basetags = readtagsformerge(
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ui, repo, fca.data().splitlines(), fn=b"base tags", keeplinenums=False
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)
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# recover the list of "lost tags" (i.e. those that were found on the base
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# revision but not on one of the revisions being merged)
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basetagset = set(basetags)
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for n, pntags in enumerate((p1tags, p2tags)):
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pntagset = set(pntags)
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pnlosttagset = basetagset - pntagset
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for t in pnlosttagset:
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pntags[t] = basetags[t]
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if pntags[t][-1][0] != hexnullid:
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pntags[t].append([hexnullid, None])
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conflictedtags = [] # for reporting purposes
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mergedtags = util.sortdict(p1tags)
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# sortdict does not implement iteritems()
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for tname, p2nodes in p2tags.items():
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if tname not in mergedtags:
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mergedtags[tname] = p2nodes
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continue
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p1nodes = mergedtags[tname]
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mergednodes = singletagmerge(p1nodes, p2nodes)
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if mergednodes is None:
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conflictedtags.append(tname)
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continue
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mergedtags[tname] = mergednodes
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if conflictedtags:
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numconflicts = len(conflictedtags)
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ui.warn(
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_(
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b'automatic .hgtags merge failed\n'
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b'the following %d tags are in conflict: %s\n'
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)
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% (numconflicts, b', '.join(sorted(conflictedtags)))
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)
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return True, 1
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writemergedtags(fcd, mergedtags)
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ui.note(_(b'.hgtags merged successfully\n'))
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return False, 0
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