templater: make strings in template expressions be "string-escape"-ed correctly...
templater: make strings in template expressions be "string-escape"-ed correctly
Changeset
64b4f0cd7336 (released with 2.8.1) fixed "recursively
evaluate string literals as templates" problem (issue4102) by moving
the location of "string-escape"-ing from "tokenizer()" to
"compiletemplate()".
But some parts in template expressions below are not processed by
"compiletemplate()", and it may cause unexpected result.
- 'expr' of 'if(expr, then, else)'
- 'expr's of 'ifeq(expr, expr, then, else)'
- 'sep' of 'join(list, sep)'
- 'text' and 'style' of 'rstdoc(text, style)'
- 'text' and 'chars' of 'strip(text, chars)'
- 'pat' and 'repl' of 'sub(pat, repl, expr)'
For example, '\n' of "{join(extras, '\n')}" is not "string-escape"-ed
and treated as a literal '\n'. This breaks "Display the contents of
the 'extra' field, one per line" example in "hg help templates".
Just "string-escape"-ing on each parts above may not work correctly,
because inside expression of nested ones already applies
"string-escape" on string literals. For example:
- "{join(files, '\n')}" doesn't return "string-escape"-ed string, but
- "{join(files, if(branch, '\n', '\n'))}" does
To fix this problem, this patch does:
- introduce "rawstring" token and "runrawstring" method to handle
strings not to be "string-escape"-ed correctly, and
- make "runstring" method return "string-escape"-ed string, and
delay "string-escape"-ing until evaluation
This patch invokes "compiletemplate()" with "strtoken=exp[0]" in
"gettemplate()", because "exp[1]" is not yet evaluated. This code path
is tested via mapping ("expr % '{template}'").
In the other hand, this patch invokes it with "strtoken='rawstring'"
in "_evalifliteral()", because "t" is the result of "arg" evaluation
and it should be "string-escape"-ed if "arg" is "string" expression.
This patch doesn't test "string-escape"-ing on 'expr' of 'if(expr,
then, else)', because it doesn't affect the result.
