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rust-cpython: move $leaked struct out of macro...
rust-cpython: move $leaked struct out of macro It wasn't easy to hack the $leaked struct since errors in macro would generate lots of compile errors. Let's make it a plain struct so we can easily extend it. PyLeakedRef keeps a more generic PyObject instead of the $name struct since it no longer has to call any specific methods implemented by the $name class. $leaked parameter in py_shared_iterator!() is kept for future change.

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cacheutil.py
22 lines | 822 B | text/x-python | PythonLexer
# scmutil.py - Mercurial core utility functions
#
# Copyright Matt Mackall <mpm@selenic.com> and other
#
# This software may be used and distributed according to the terms of the
# GNU General Public License version 2 or any later version.
from __future__ import absolute_import
from . import repoview
def cachetocopy(srcrepo):
"""return the list of cache file valuable to copy during a clone"""
# In local clones we're copying all nodes, not just served
# ones. Therefore copy all branch caches over.
cachefiles = [b'branch2']
cachefiles += [b'branch2-%s' % f for f in repoview.filtertable]
cachefiles += [b'rbc-names-v1', b'rbc-revs-v1']
cachefiles += [b'tags2']
cachefiles += [b'tags2-%s' % f for f in repoview.filtertable]
cachefiles += [b'hgtagsfnodes1']
return cachefiles