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mq: look for modified subrepos when checking for local changes...
mq: look for modified subrepos when checking for local changes It was possible to apply, unapply, fold, patches (etc) with modified subrepos, which resulted in surprising behavior. For example it was easy to apply a patch with a modified subrepo, and then the refresh it and accidentally end up including the modified subrepo on the refreshed patch. A test has been added to verify this new check. # HG changeset patch # User Angel Ezquerra <angel.ezquerra@gmail.com> # Date 1375742979 -7200 # Tue Aug 06 00:49:39 2013 +0200 # Node ID a5c90acff5e61aae714ba6c9457d766c54b4f124 # Parent 6ac206fb6f27492a98f46bbff090407ee1b1de72 mq: look for modified subrepos when checking for local changes It was possible to apply, unapply, fold, patches (etc) with modified subrepos, which resulted in surprising behavior. For example it was easy to apply a patch with a modified subrepo, and then the refresh it and accidentally end up including the modified subrepo on the refreshed patch. A test has been added to verify this new check.

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dicthelpers.py
55 lines | 1.6 KiB | text/x-python | PythonLexer
# dicthelpers.py - helper routines for Python dicts
#
# Copyright 2013 Facebook
#
# This software may be used and distributed according to the terms of the
# GNU General Public License version 2 or any later version.
def diff(d1, d2, default=None):
'''Return all key-value pairs that are different between d1 and d2.
This includes keys that are present in one dict but not the other, and
keys whose values are different. The return value is a dict with values
being pairs of values from d1 and d2 respectively, and missing values
treated as default, so if a value is missing from one dict and the same as
default in the other, it will not be returned.'''
res = {}
if d1 is d2:
# same dict, so diff is empty
return res
for k1, v1 in d1.iteritems():
v2 = d2.get(k1, default)
if v1 != v2:
res[k1] = (v1, v2)
for k2 in d2:
if k2 not in d1:
v2 = d2[k2]
if v2 != default:
res[k2] = (default, v2)
return res
def join(d1, d2, default=None):
'''Return all key-value pairs from both d1 and d2.
This is akin to an outer join in relational algebra. The return value is a
dict with values being pairs of values from d1 and d2 respectively, and
missing values represented as default.'''
res = {}
for k1, v1 in d1.iteritems():
if k1 in d2:
res[k1] = (v1, d2[k1])
else:
res[k1] = (v1, default)
if d1 is d2:
return res
for k2 in d2:
if k2 not in d1:
res[k2] = (default, d2[k2])
return res