##// END OF EJS Templates
branchcache: add a "pure topological head" fast path...
branchcache: add a "pure topological head" fast path In a narrow but actually quick common case, all topological heads are all on the same branch and all open. In this case, computing the branch map is very simple. We can quickly detect situation where this situation will not change. So we update the V3 format to be able to express this situation and upgrade the update code to detect we remains in that mode. The branch cache is populated with the actual value when the branch map is accessed, but the update_disk method can do the update without needing to populate it.

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ro.py
67 lines | 2.0 KiB | text/x-python | PythonLexer
##############################################################################
#
# Copyright (c) 2003 Zope Foundation and Contributors.
# All Rights Reserved.
#
# This software is subject to the provisions of the Zope Public License,
# Version 2.1 (ZPL). A copy of the ZPL should accompany this distribution.
# THIS SOFTWARE IS PROVIDED "AS IS" AND ANY AND ALL EXPRESS OR IMPLIED
# WARRANTIES ARE DISCLAIMED, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED
# WARRANTIES OF TITLE, MERCHANTABILITY, AGAINST INFRINGEMENT, AND FITNESS
# FOR A PARTICULAR PURPOSE.
#
##############################################################################
"""Compute a resolution order for an object and its bases
"""
from __future__ import absolute_import
__docformat__ = 'restructuredtext'
def _mergeOrderings(orderings):
"""Merge multiple orderings so that within-ordering order is preserved
Orderings are constrained in such a way that if an object appears
in two or more orderings, then the suffix that begins with the
object must be in both orderings.
For example:
>>> _mergeOrderings([
... ['x', 'y', 'z'],
... ['q', 'z'],
... [1, 3, 5],
... ['z']
... ])
['x', 'y', 'q', 1, 3, 5, 'z']
"""
seen = {}
result = []
for ordering in reversed(orderings):
for o in reversed(ordering):
if o not in seen:
seen[o] = 1
result.insert(0, o)
return result
def _flatten(ob):
result = [ob]
i = 0
for ob in iter(result):
i += 1
# The recursive calls can be avoided by inserting the base classes
# into the dynamically growing list directly after the currently
# considered object; the iterator makes sure this will keep working
# in the future, since it cannot rely on the length of the list
# by definition.
result[i:i] = ob.__bases__
return result
def ro(object):
"""Compute a "resolution order" for an object
"""
return _mergeOrderings([_flatten(object)])