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contrib: don't hardcode path to bash interpreter...
contrib: don't hardcode path to bash interpreter Use the env binary to figure out the correct bash to use. Certain systems ships with an ancient version of bash, but the user might have installed a newer one that is earlier in $PATH. For example the current version of Mac OS X ships version 3.2.51 of bash, which does not understand new fancy builtins such as readarray. A user might install a newer version of bash, use that as their shell and add that path before bin.

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scmposix.py
32 lines | 877 B | text/x-python | PythonLexer
import sys, os
import osutil
def _rcfiles(path):
rcs = [os.path.join(path, 'hgrc')]
rcdir = os.path.join(path, 'hgrc.d')
try:
rcs.extend([os.path.join(rcdir, f)
for f, kind in osutil.listdir(rcdir)
if f.endswith(".rc")])
except OSError:
pass
return rcs
def systemrcpath():
path = []
if sys.platform == 'plan9':
root = 'lib/mercurial'
else:
root = 'etc/mercurial'
# old mod_python does not set sys.argv
if len(getattr(sys, 'argv', [])) > 0:
p = os.path.dirname(os.path.dirname(sys.argv[0]))
path.extend(_rcfiles(os.path.join(p, root)))
path.extend(_rcfiles('/' + root))
return path
def userrcpath():
if sys.platform == 'plan9':
return [os.environ['home'] + '/lib/hgrc']
else:
return [os.path.expanduser('~/.hgrc')]