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repair: fix an `isinstance(nodelist, str)` check for py3...
repair: fix an `isinstance(nodelist, str)` check for py3 All of the callers appear to pass a list, so this doesn't fix anything in core hg. But maybe out of tree extensions use this shortcut. Differential Revision: https://phab.mercurial-scm.org/D7533

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ro.py
67 lines | 2.0 KiB | text/x-python | PythonLexer
##############################################################################
#
# Copyright (c) 2003 Zope Foundation and Contributors.
# All Rights Reserved.
#
# This software is subject to the provisions of the Zope Public License,
# Version 2.1 (ZPL). A copy of the ZPL should accompany this distribution.
# THIS SOFTWARE IS PROVIDED "AS IS" AND ANY AND ALL EXPRESS OR IMPLIED
# WARRANTIES ARE DISCLAIMED, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED
# WARRANTIES OF TITLE, MERCHANTABILITY, AGAINST INFRINGEMENT, AND FITNESS
# FOR A PARTICULAR PURPOSE.
#
##############################################################################
"""Compute a resolution order for an object and its bases
"""
from __future__ import absolute_import
__docformat__ = 'restructuredtext'
def _mergeOrderings(orderings):
"""Merge multiple orderings so that within-ordering order is preserved
Orderings are constrained in such a way that if an object appears
in two or more orderings, then the suffix that begins with the
object must be in both orderings.
For example:
>>> _mergeOrderings([
... ['x', 'y', 'z'],
... ['q', 'z'],
... [1, 3, 5],
... ['z']
... ])
['x', 'y', 'q', 1, 3, 5, 'z']
"""
seen = {}
result = []
for ordering in reversed(orderings):
for o in reversed(ordering):
if o not in seen:
seen[o] = 1
result.insert(0, o)
return result
def _flatten(ob):
result = [ob]
i = 0
for ob in iter(result):
i += 1
# The recursive calls can be avoided by inserting the base classes
# into the dynamically growing list directly after the currently
# considered object; the iterator makes sure this will keep working
# in the future, since it cannot rely on the length of the list
# by definition.
result[i:i] = ob.__bases__
return result
def ro(object):
"""Compute a "resolution order" for an object
"""
return _mergeOrderings([_flatten(object)])