upstream/mercurial-mirror Files · mercurial/strutil.py

convert: when converting from monotone, use the number 1 for close in extras...

convert: when converting from monotone, use the number 1 for close in extras Monotone used '1' for close while core Mercurial use 1. Now, for consistency, use the same value everywhere. It will be stored as a string anyway and the change will not make any real difference. (The actual value of 'close' doesn't matter as long as extras has such a key.)

Matt Mackall - - Load All Authors

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      # strutil.py - string utilities for Mercurial

      #

      # Copyright 2006 Vadim Gelfer <vadim.gelfer@gmail.com>

      #

      # This software may be used and distributed according to the terms of the

      # GNU General Public License version 2 or any later version.

      def findall(haystack, needle, start=0, end=None):

          if end is None:

              end = len(haystack)

          if end < 0:

              end += len(haystack)

          if start < 0:

              start += len(haystack)

          while start < end:

              c = haystack.find(needle, start, end)

              if c == -1:

                  break

              yield c

              start = c + 1

      def rfindall(haystack, needle, start=0, end=None):

          if end is None:

              end = len(haystack)

          if end < 0:

              end += len(haystack)

          if start < 0:

              start += len(haystack)

          while end >= 0:

              c = haystack.rfind(needle, start, end)

              if c == -1:

                  break

              yield c

              end = c - 1

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				# strutil.py - string utilities for Mercurial
				#
				# Copyright 2006 Vadim Gelfer <vadim.gelfer@gmail.com>
				#
				# This software may be used and distributed according to the terms of the
				# GNU General Public License version 2 or any later version.

				def findall(haystack, needle, start=0, end=None):
				if end is None:
				end = len(haystack)
				if end < 0:
				end += len(haystack)
				if start < 0:
				start += len(haystack)
				while start < end:
				c = haystack.find(needle, start, end)
				if c == -1:
				break
				yield c
				start = c + 1

				def rfindall(haystack, needle, start=0, end=None):
				if end is None:
				end = len(haystack)
				if end < 0:
				end += len(haystack)
				if start < 0:
				start += len(haystack)
				while end >= 0:
				c = haystack.rfind(needle, start, end)
				if c == -1:
				break
				yield c
				end = c - 1