##// END OF EJS Templates
destroyed: drop complex branchcache rebuilt logic...
destroyed: drop complex branchcache rebuilt logic The strip code used a trick to lower the cost of branchcache update after a strip. However is less necessary since we have branchcache collaboration. Invalid branchcache are likely to be cheaply rebuilt again a near subset of the repo. Moreover, this trick would need update to be relevant in the now filtered repository world. It currently update the unfiltered branchcache that few people cares about. Make it smarter on that aspect would need complexes update of the calling logic So this mechanism is: - Arguably needed, - Currently irrelevant, - Hard to update and I'm dropping it. We now update the branchcache in all case by courtesy of the read only reader. This changeset have a few expected impact on the testsuite are different cache are updated.

File last commit:

r12387:4f8067c9 default
r18395:904b7109 default
Show More
diffhelpers.py
60 lines | 1.5 KiB | text/x-python | PythonLexer
# diffhelpers.py - pure Python implementation of diffhelpers.c
#
# Copyright 2009 Matt Mackall <mpm@selenic.com> and others
#
# This software may be used and distributed according to the terms of the
# GNU General Public License version 2 or any later version.
def addlines(fp, hunk, lena, lenb, a, b):
while True:
todoa = lena - len(a)
todob = lenb - len(b)
num = max(todoa, todob)
if num == 0:
break
for i in xrange(num):
s = fp.readline()
c = s[0]
if s == "\\ No newline at end of file\n":
fix_newline(hunk, a, b)
continue
if c == "\n":
# Some patches may be missing the control char
# on empty lines. Supply a leading space.
s = " \n"
hunk.append(s)
if c == "+":
b.append(s[1:])
elif c == "-":
a.append(s)
else:
b.append(s[1:])
a.append(s)
return 0
def fix_newline(hunk, a, b):
l = hunk[-1]
# tolerate CRLF in last line
if l.endswith('\r\n'):
hline = l[:-2]
else:
hline = l[:-1]
c = hline[0]
if c in " +":
b[-1] = hline[1:]
if c in " -":
a[-1] = hline
hunk[-1] = hline
return 0
def testhunk(a, b, bstart):
alen = len(a)
blen = len(b)
if alen > blen - bstart:
return -1
for i in xrange(alen):
if a[i][1:] != b[i + bstart]:
return -1
return 0