upstream/mercurial-mirror Files · mercurial/dicthelpers.py

filecontext: use 'is not None' to check for filelog existence...

filecontext: use 'is not None' to check for filelog existence Previously we used 'if filelog:' to check if the filelog existed. If the instance did exist, this pattern then calls len() on the filelog to see if it is empty. I'm developing a filelog replacement that doesn't have len() implemented, so it's better to do an explicit 'is not None' check here instead. Also change _changeid() to return the _changeid attribute if it has it. Previously it would try to obtain it from the _changectx(), and if that did not exist it would construct the _changectx() using the linkrev. In the extension I'm working on, filectx's don't have easy access to linkrevs so avoiding this when possible is better.

Siddharth Agarwal - - Load All Authors

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      # dicthelpers.py - helper routines for Python dicts

      #

      # Copyright 2013 Facebook

      #

      # This software may be used and distributed according to the terms of the

      # GNU General Public License version 2 or any later version.

      def diff(d1, d2, default=None):

          '''Return all key-value pairs that are different between d1 and d2.

          This includes keys that are present in one dict but not the other, and

          keys whose values are different. The return value is a dict with values

          being pairs of values from d1 and d2 respectively, and missing values

          treated as default, so if a value is missing from one dict and the same as

          default in the other, it will not be returned.'''

          res = {}

          if d1 is d2:

              # same dict, so diff is empty

              return res

          for k1, v1 in d1.iteritems():

              v2 = d2.get(k1, default)

              if v1 != v2:

                  res[k1] = (v1, v2)

          for k2 in d2:

              if k2 not in d1:

                  v2 = d2[k2]

                  if v2 != default:

                      res[k2] = (default, v2)

          return res

      def join(d1, d2, default=None):

          '''Return all key-value pairs from both d1 and d2.

          This is akin to an outer join in relational algebra. The return value is a

          dict with values being pairs of values from d1 and d2 respectively, and

          missing values represented as default.'''

          res = {}

          for k1, v1 in d1.iteritems():

              if k1 in d2:

                  res[k1] = (v1, d2[k1])

              else:

                  res[k1] = (v1, default)

          if d1 is d2:

              return res

          for k2 in d2:

              if k2 not in d1:

                  res[k2] = (default, d2[k2])

          return res

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				# dicthelpers.py - helper routines for Python dicts
				#
				# Copyright 2013 Facebook
				#
				# This software may be used and distributed according to the terms of the
				# GNU General Public License version 2 or any later version.

				def diff(d1, d2, default=None):
				'''Return all key-value pairs that are different between d1 and d2.

				This includes keys that are present in one dict but not the other, and
				keys whose values are different. The return value is a dict with values
				being pairs of values from d1 and d2 respectively, and missing values
				treated as default, so if a value is missing from one dict and the same as
				default in the other, it will not be returned.'''
				res = {}
				if d1 is d2:
				# same dict, so diff is empty
				return res

				for k1, v1 in d1.iteritems():
				v2 = d2.get(k1, default)
				if v1 != v2:
				res[k1] = (v1, v2)

				for k2 in d2:
				if k2 not in d1:
				v2 = d2[k2]
				if v2 != default:
				res[k2] = (default, v2)

				return res

				def join(d1, d2, default=None):
				'''Return all key-value pairs from both d1 and d2.

				This is akin to an outer join in relational algebra. The return value is a
				dict with values being pairs of values from d1 and d2 respectively, and
				missing values represented as default.'''
				res = {}

				for k1, v1 in d1.iteritems():
				if k1 in d2:
				res[k1] = (v1, d2[k1])
				else:
				res[k1] = (v1, default)

				if d1 is d2:
				return res

				for k2 in d2:
				if k2 not in d1:
				res[k2] = (default, d2[k2])

				return res