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filelog: store filename directly on revlog instance...
filelog: store filename directly on revlog instance This attribute is only used by LFS. It is used by one of the revlog flag processor functions, which gets an instance of the revlog - not the file storage type. So, it makes sense to store this attribute on the revlog instead of the filelog. With this change, I'm pretty confident that LFS is no longer directly accessing file storage interface members that are revlog centric. i.e. it gets us one step closer to eliminating revlog-centric APIs from the file storage interface! Differential Revision: https://phab.mercurial-scm.org/D4715

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ro.py
67 lines | 2.0 KiB | text/x-python | PythonLexer
##############################################################################
#
# Copyright (c) 2003 Zope Foundation and Contributors.
# All Rights Reserved.
#
# This software is subject to the provisions of the Zope Public License,
# Version 2.1 (ZPL). A copy of the ZPL should accompany this distribution.
# THIS SOFTWARE IS PROVIDED "AS IS" AND ANY AND ALL EXPRESS OR IMPLIED
# WARRANTIES ARE DISCLAIMED, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED
# WARRANTIES OF TITLE, MERCHANTABILITY, AGAINST INFRINGEMENT, AND FITNESS
# FOR A PARTICULAR PURPOSE.
#
##############################################################################
"""Compute a resolution order for an object and its bases
"""
from __future__ import absolute_import
__docformat__ = 'restructuredtext'
def _mergeOrderings(orderings):
"""Merge multiple orderings so that within-ordering order is preserved
Orderings are constrained in such a way that if an object appears
in two or more orderings, then the suffix that begins with the
object must be in both orderings.
For example:
>>> _mergeOrderings([
... ['x', 'y', 'z'],
... ['q', 'z'],
... [1, 3, 5],
... ['z']
... ])
['x', 'y', 'q', 1, 3, 5, 'z']
"""
seen = {}
result = []
for ordering in reversed(orderings):
for o in reversed(ordering):
if o not in seen:
seen[o] = 1
result.insert(0, o)
return result
def _flatten(ob):
result = [ob]
i = 0
for ob in iter(result):
i += 1
# The recursive calls can be avoided by inserting the base classes
# into the dynamically growing list directly after the currently
# considered object; the iterator makes sure this will keep working
# in the future, since it cannot rely on the length of the list
# by definition.
result[i:i] = ob.__bases__
return result
def ro(object):
"""Compute a "resolution order" for an object
"""
return _mergeOrderings([_flatten(object)])