##// END OF EJS Templates
debugdeltachain: stop summing the same chain over and over...
debugdeltachain: stop summing the same chain over and over Before this patch, delta chain size was computed from scratch for each chain, disregarding the fact very likely already computed the same of length-1 prefix for another revisions. We not cache delta chain size and shortcut the computation when we see them. Just for my mercurial-devel clone, this move the computation from about 17.5 second to about 4.8 seconds.

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r51243:af776c3d stable
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pushkey.py
70 lines | 1.6 KiB | text/x-python | PythonLexer
# pushkey.py - dispatching for pushing and pulling keys
#
# Copyright 2010 Olivia Mackall <olivia@selenic.com>
#
# This software may be used and distributed according to the terms of the
# GNU General Public License version 2 or any later version.
from . import (
bookmarks,
encoding,
obsolete,
phases,
)
def _nslist(repo):
n = {}
for k in _namespaces:
n[k] = b""
if not obsolete.isenabled(repo, obsolete.exchangeopt):
n.pop(b'obsolete')
return n
_namespaces = {
b"namespaces": (lambda *x: False, _nslist),
b"bookmarks": (bookmarks.pushbookmark, bookmarks.listbookmarks),
b"phases": (phases.pushphase, phases.listphases),
b"obsolete": (obsolete.pushmarker, obsolete.listmarkers),
}
def register(namespace, pushkey, listkeys):
_namespaces[namespace] = (pushkey, listkeys)
def _get(namespace):
return _namespaces.get(namespace, (lambda *x: False, lambda *x: {}))
def push(repo, namespace, key, old, new):
'''should succeed iff value was old'''
pk = _get(namespace)[0]
return pk(repo, key, old, new)
def list(repo, namespace):
'''return a dict'''
lk = _get(namespace)[1]
return lk(repo)
encode = encoding.fromlocal
decode = encoding.tolocal
def encodekeys(keys):
"""encode the content of a pushkey namespace for exchange over the wire"""
return b'\n'.join([b'%s\t%s' % (encode(k), encode(v)) for k, v in keys])
def decodekeys(data):
"""decode the content of a pushkey namespace from exchange over the wire"""
result = {}
for l in data.splitlines():
k, v = l.split(b'\t')
result[decode(k)] = decode(v)
return result