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# changelog bisection for mercurial
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#
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# Copyright 2007 Matt Mackall
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# Copyright 2005, 2006 Benoit Boissinot <benoit.boissinot@ens-lyon.org>
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# Inspired by git bisect, extension skeleton taken from mq.py.
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#
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# This software may be used and distributed according to the terms
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# of the GNU General Public License, incorporated herein by reference.
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from i18n import _
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import hg, util
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def bisect(changelog, state):
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clparents = changelog.parentrevs
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skip = dict.fromkeys([changelog.rev(n) for n in state['skip']])
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def buildancestors(bad, good):
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# only the earliest bad revision matters
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badrev = min([changelog.rev(n) for n in bad])
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goodrevs = [changelog.rev(n) for n in good]
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# build ancestors array
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ancestors = [[]] * (changelog.count() + 1) # an extra for [-1]
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# clear good revs from array
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for node in goodrevs:
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ancestors[node] = None
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for rev in xrange(changelog.count(), -1, -1):
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if ancestors[rev] is None:
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for prev in clparents(rev):
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ancestors[prev] = None
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if ancestors[badrev] is None:
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return badrev, None
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return badrev, ancestors
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good = 0
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badrev, ancestors = buildancestors(state['bad'], state['good'])
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if not ancestors: # looking for bad to good transition?
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good = 1
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badrev, ancestors = buildancestors(state['good'], state['bad'])
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bad = changelog.node(badrev)
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if not ancestors: # now we're confused
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raise util.Abort(_("Inconsistent state, %s:%s is good and bad")
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% (badrev, hg.short(bad)))
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# build children dict
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children = {}
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visit = [badrev]
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candidates = []
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while visit:
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rev = visit.pop(0)
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if ancestors[rev] == []:
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candidates.append(rev)
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for prev in clparents(rev):
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if prev != -1:
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if prev in children:
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children[prev].append(rev)
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else:
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children[prev] = [rev]
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visit.append(prev)
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candidates.sort()
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# have we narrowed it down to one entry?
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tot = len(candidates)
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if tot == 1:
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return (bad, 0, good)
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perfect = tot / 2
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# find the best node to test
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best_rev = None
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best_len = -1
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poison = {}
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for rev in candidates:
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if rev in poison:
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for c in children.get(rev, []):
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poison[c] = True # poison children
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continue
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a = ancestors[rev] or [rev]
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ancestors[rev] = None
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x = len(a) # number of ancestors
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y = tot - x # number of non-ancestors
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value = min(x, y) # how good is this test?
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if value > best_len and rev not in skip:
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best_len = value
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best_rev = rev
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if value == perfect: # found a perfect candidate? quit early
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break
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if y < perfect: # all downhill from here?
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for c in children.get(rev, []):
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poison[c] = True # poison children
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continue
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for c in children.get(rev, []):
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if ancestors[c]:
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ancestors[c] = dict.fromkeys(ancestors[c] + a).keys()
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else:
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ancestors[c] = a + [c]
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assert best_rev is not None
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best_node = changelog.node(best_rev)
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return (best_node, tot, good)
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