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subrepo: change default path in hgrc of subrepo after cloning...
subrepo: change default path in hgrc of subrepo after cloning Previous behavior was to put in the cloned subrepos the path found in the original main repo. However it isn't valid for relative path and it seems more logical to reference instead the subrepos working copy path of the original main repo.

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test-bundle-vs-outgoing
84 lines | 1.5 KiB | text/plain | TextLexer
/ tests / test-bundle-vs-outgoing
#!/bin/sh
# this structure seems to tickle a bug in bundle's search for
# changesets, so first we have to recreate it
#
# o 8
# |
# | o 7
# | |
# | o 6
# |/|
# o | 5
# | |
# o | 4
# | |
# | o 3
# | |
# | o 2
# |/
# o 1
# |
# o 0
mkrev()
{
revno=$1
echo "rev $revno"
echo "rev $revno" > foo.txt
hg -q ci -m"rev $revno"
}
set -e
echo "% setup test repo1"
hg init repo1
cd repo1
echo "rev 0" > foo.txt
hg ci -Am"rev 0"
mkrev 1
# first branch
mkrev 2
mkrev 3
# back to rev 1 to create second branch
hg up -r1
mkrev 4
mkrev 5
# merge first branch to second branch
hg up -C -r5
HGMERGE=internal:local hg merge
echo "merge rev 5, rev 3" > foo.txt
hg ci -m"merge first branch to second branch"
# one more commit following the merge
mkrev 7
# back to "second branch" to make another head
hg up -r5
mkrev 8
echo "[extensions]" >> $HGRCPATH
echo "graphlog=" >> $HGRCPATH
echo "% the story so far"
hg glog --template "{rev}\n"
# check that "hg outgoing" really does the right thing
echo "% sanity check of outgoing: expect revs 4 5 6 7 8"
hg clone -r3 . ../repo2
# this should (and does) report 5 outgoing revisions: 4 5 6 7 8
hg outgoing --template "{rev}\n" ../repo2
echo "% test bundle (destination repo): expect 5 revisions"
# this should bundle the same 5 revisions that outgoing reported, but it
# actually bundles 7
hg bundle foo.bundle ../repo2
echo "% test bundle (base revision): expect 5 revisions"
# this should (and does) give exactly the same result as bundle
# with a destination repo... i.e. it's wrong too
hg bundle --base 3 foo.bundle