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patch: support diff data loss detection and upgrade...
patch: support diff data loss detection and upgrade In worst case, generating diff in upgrade mode can be two times more expensive than generating it in git mode directly: we may have to regenerate the whole diff again whenever a git feature is detected. Also, the first diff attempt is completely buffered instead of being streamed. That said, even without having profiled it yet, I am convinced we can fast-path the upgrade mode if necessary were it to be used in regular diff commands, and not only in mq where avoiding data loss is worth the price.

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ancestor.py
86 lines | 2.4 KiB | text/x-python | PythonLexer
# ancestor.py - generic DAG ancestor algorithm for mercurial
#
# Copyright 2006 Matt Mackall <mpm@selenic.com>
#
# This software may be used and distributed according to the terms of the
# GNU General Public License version 2, incorporated herein by reference.
import heapq
def ancestor(a, b, pfunc):
"""
return a minimal-distance ancestor of nodes a and b, or None if there is no
such ancestor. Note that there can be several ancestors with the same
(minimal) distance, and the one returned is arbitrary.
pfunc must return a list of parent vertices for a given vertex
"""
if a == b:
return a
# find depth from root of all ancestors
parentcache = {}
visit = [a, b]
depth = {}
while visit:
vertex = visit[-1]
pl = pfunc(vertex)
parentcache[vertex] = pl
if not pl:
depth[vertex] = 0
visit.pop()
else:
for p in pl:
if p == a or p == b: # did we find a or b as a parent?
return p # we're done
if p not in depth:
visit.append(p)
if visit[-1] == vertex:
depth[vertex] = min([depth[p] for p in pl]) - 1
visit.pop()
# traverse ancestors in order of decreasing distance from root
def ancestors(vertex):
h = [(depth[vertex], vertex)]
seen = set()
while h:
d, n = heapq.heappop(h)
if n not in seen:
seen.add(n)
yield (d, n)
for p in parentcache[n]:
heapq.heappush(h, (depth[p], p))
def generations(vertex):
sg, s = None, set()
for g, v in ancestors(vertex):
if g != sg:
if sg:
yield sg, s
sg, s = g, set((v,))
else:
s.add(v)
yield sg, s
x = generations(a)
y = generations(b)
gx = x.next()
gy = y.next()
# increment each ancestor list until it is closer to root than
# the other, or they match
try:
while 1:
if gx[0] == gy[0]:
for v in gx[1]:
if v in gy[1]:
return v
gy = y.next()
gx = x.next()
elif gx[0] > gy[0]:
gy = y.next()
else:
gx = x.next()
except StopIteration:
return None