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rust-nodemap: automatically use the rust index for persistent nodemap...
rust-nodemap: automatically use the rust index for persistent nodemap The persistent nodemap requires the rust index to be used to provides any gains. So we automatically enable it for revlog using the persistent nodemap. We keep it off for other revset because now that the rust revlog fully initialise the nodemap using it everywhere introduce a fairly significant regression (eg: hg diff moving from 0.8s to 2.3s on mozilla-try) Differential Revision: https://phab.mercurial-scm.org/D8164

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ro.py
67 lines | 2.0 KiB | text/x-python | PythonLexer
##############################################################################
#
# Copyright (c) 2003 Zope Foundation and Contributors.
# All Rights Reserved.
#
# This software is subject to the provisions of the Zope Public License,
# Version 2.1 (ZPL). A copy of the ZPL should accompany this distribution.
# THIS SOFTWARE IS PROVIDED "AS IS" AND ANY AND ALL EXPRESS OR IMPLIED
# WARRANTIES ARE DISCLAIMED, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED
# WARRANTIES OF TITLE, MERCHANTABILITY, AGAINST INFRINGEMENT, AND FITNESS
# FOR A PARTICULAR PURPOSE.
#
##############################################################################
"""Compute a resolution order for an object and its bases
"""
from __future__ import absolute_import
__docformat__ = 'restructuredtext'
def _mergeOrderings(orderings):
"""Merge multiple orderings so that within-ordering order is preserved
Orderings are constrained in such a way that if an object appears
in two or more orderings, then the suffix that begins with the
object must be in both orderings.
For example:
>>> _mergeOrderings([
... ['x', 'y', 'z'],
... ['q', 'z'],
... [1, 3, 5],
... ['z']
... ])
['x', 'y', 'q', 1, 3, 5, 'z']
"""
seen = {}
result = []
for ordering in reversed(orderings):
for o in reversed(ordering):
if o not in seen:
seen[o] = 1
result.insert(0, o)
return result
def _flatten(ob):
result = [ob]
i = 0
for ob in iter(result):
i += 1
# The recursive calls can be avoided by inserting the base classes
# into the dynamically growing list directly after the currently
# considered object; the iterator makes sure this will keep working
# in the future, since it cannot rely on the length of the list
# by definition.
result[i:i] = ob.__bases__
return result
def ro(object):
"""Compute a "resolution order" for an object
"""
return _mergeOrderings([_flatten(object)])