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strip: make repair.strip transactional to avoid repository corruption...
strip: make repair.strip transactional to avoid repository corruption Uses a transaction instance from the local repository to journal the truncation of revlog files, such that if a strip only partially completes, hg recover will be able to finish the truncate of all the files. The potential unbundling of changes that have been backed up to be restored later will, in case of an error, have to be unbundled manually. The difference is that it will be possible to recover the repository state so the unbundle can actually succeed.

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base85.py
74 lines | 1.9 KiB | text/x-python | PythonLexer
# base85.py: pure python base85 codec
#
# Copyright (C) 2009 Brendan Cully <brendan@kublai.com>
#
# This software may be used and distributed according to the terms of
# the GNU General Public License, incorporated herein by reference.
import struct
_b85chars = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ" \
"abcdefghijklmnopqrstuvwxyz!#$%&()*+-;<=>?@^_`{|}~"
_b85chars2 = [(a + b) for a in _b85chars for b in _b85chars]
_b85dec = {}
def _mkb85dec():
for i in range(len(_b85chars)):
_b85dec[_b85chars[i]] = i
def b85encode(text, pad=False):
"""encode text in base85 format"""
l = len(text)
r = l % 4
if r:
text += '\0' * (4 - r)
longs = len(text) >> 2
words = struct.unpack('>%dL' % (longs), text)
out = ''.join(_b85chars[(word / 52200625) % 85] +
_b85chars2[(word / 7225) % 7225] +
_b85chars2[word % 7225]
for word in words)
if pad:
return out
# Trim padding
olen = l % 4
if olen:
olen += 1
olen += l / 4 * 5
return out[:olen]
def b85decode(text):
"""decode base85-encoded text"""
if not _b85dec:
_mkb85dec()
l = len(text)
out = []
for i in range(0, len(text), 5):
chunk = text[i:i+5]
acc = 0
for j in range(len(chunk)):
try:
acc = acc * 85 + _b85dec[chunk[j]]
except KeyError:
raise TypeError('Bad base85 character at byte %d' % (i + j))
if acc > 4294967295:
raise OverflowError('Base85 overflow in hunk starting at byte %d' % i)
out.append(acc)
# Pad final chunk if necessary
cl = l % 5
if cl:
acc *= 85 ** (5 - cl)
if cl > 1:
acc += 0xffffff >> (cl - 2) * 8
out[-1] = acc
out = struct.pack('>%dL' % (len(out)), *out)
if cl:
out = out[:-(5 - cl)]
return out