##// END OF EJS Templates
progress: use a verb (+noun) in present participle
progress: use a verb (+noun) in present participle

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parentrevspec.py
96 lines | 3.1 KiB | text/x-python | PythonLexer
# Mercurial extension to make it easy to refer to the parent of a revision
#
# Copyright (C) 2007 Alexis S. L. Carvalho <alexis@cecm.usp.br>
#
# This software may be used and distributed according to the terms of the
# GNU General Public License version 2 or any later version.
'''interpret suffixes to refer to ancestor revisions
This extension allows you to use git-style suffixes to refer to the
ancestors of a specific revision.
For example, if you can refer to a revision as "foo", then::
foo^N = Nth parent of foo
foo^0 = foo
foo^1 = first parent of foo
foo^2 = second parent of foo
foo^ = foo^1
foo~N = Nth first grandparent of foo
foo~0 = foo
foo~1 = foo^1 = foo^ = first parent of foo
foo~2 = foo^1^1 = foo^^ = first parent of first parent of foo
'''
from mercurial import error
def reposetup(ui, repo):
if not repo.local():
return
class parentrevspecrepo(repo.__class__):
def lookup(self, key):
try:
_super = super(parentrevspecrepo, self)
return _super.lookup(key)
except error.RepoError:
pass
circ = key.find('^')
tilde = key.find('~')
if circ < 0 and tilde < 0:
raise
elif circ >= 0 and tilde >= 0:
end = min(circ, tilde)
else:
end = max(circ, tilde)
cl = self.changelog
base = key[:end]
try:
node = _super.lookup(base)
except error.RepoError:
# eek - reraise the first error
return _super.lookup(key)
rev = cl.rev(node)
suffix = key[end:]
i = 0
while i < len(suffix):
# foo^N => Nth parent of foo
# foo^0 == foo
# foo^1 == foo^ == 1st parent of foo
# foo^2 == 2nd parent of foo
if suffix[i] == '^':
j = i + 1
p = cl.parentrevs(rev)
if j < len(suffix) and suffix[j].isdigit():
j += 1
n = int(suffix[i + 1:j])
if n > 2 or n == 2 and p[1] == -1:
raise
else:
n = 1
if n:
rev = p[n - 1]
i = j
# foo~N => Nth first grandparent of foo
# foo~0 = foo
# foo~1 = foo^1 == foo^ == 1st parent of foo
# foo~2 = foo^1^1 == foo^^ == 1st parent of 1st parent of foo
elif suffix[i] == '~':
j = i + 1
while j < len(suffix) and suffix[j].isdigit():
j += 1
if j == i + 1:
raise
n = int(suffix[i + 1:j])
for k in xrange(n):
rev = cl.parentrevs(rev)[0]
i = j
else:
raise
return cl.node(rev)
repo.__class__ = parentrevspecrepo