##// END OF EJS Templates
test-pathencode: randomize length of each path component...
test-pathencode: randomize length of each path component This makes it possible for long and short components to exist in the same path. This also makes shorter path components more likely. For randint(1, randint(1, n)), the likelihood that one sees a number k (1 <= k <= n) is 1/n * (\sum_{k=i}^n 1/i). This decreases with k, much like in the real world where shorter paths are more common than longer ones. The previous fix and this one together cause issue3958 to be detected by this test with reasonable frequency. When this test was run 100 times in a loop, the issue was detected 30 of those times.

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peer.py
46 lines | 1.3 KiB | text/x-python | PythonLexer
# peer.py - repository base classes for mercurial
#
# Copyright 2005, 2006 Matt Mackall <mpm@selenic.com>
# Copyright 2006 Vadim Gelfer <vadim.gelfer@gmail.com>
#
# This software may be used and distributed according to the terms of the
# GNU General Public License version 2 or any later version.
from i18n import _
import error
class peerrepository(object):
def capable(self, name):
'''tell whether repo supports named capability.
return False if not supported.
if boolean capability, return True.
if string capability, return string.'''
caps = self._capabilities()
if name in caps:
return True
name_eq = name + '='
for cap in caps:
if cap.startswith(name_eq):
return cap[len(name_eq):]
return False
def requirecap(self, name, purpose):
'''raise an exception if the given capability is not present'''
if not self.capable(name):
raise error.CapabilityError(
_('cannot %s; remote repository does not '
'support the %r capability') % (purpose, name))
def local(self):
'''return peer as a localrepo, or None'''
return None
def peer(self):
return self
def canpush(self):
return True
def close(self):
pass