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strip: move bookmarks to nearest ancestor rather than '.'...
strip: move bookmarks to nearest ancestor rather than '.' If you've got this graph: 0-1-2 \ 3 and 3 is checked out, 2 is bookmarked with "broken", and you do "hg strip 2", the bookmark will move to 3, not 1. That's always struck me as a bug. This change makes bookmarks move to the tipmost ancestor of the stripped set rather than the currently-checked-out revision, which is what I always expected should happen.

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test-ui-verbosity.py
47 lines | 1.3 KiB | text/x-python | PythonLexer
/ tests / test-ui-verbosity.py
import os
from mercurial import ui
hgrc = os.environ['HGRCPATH']
f = open(hgrc)
basehgrc = f.read()
f.close()
print ' hgrc settings command line options final result '
print ' quiet verbo debug quiet verbo debug quiet verbo debug'
for i in xrange(64):
hgrc_quiet = bool(i & 1<<0)
hgrc_verbose = bool(i & 1<<1)
hgrc_debug = bool(i & 1<<2)
cmd_quiet = bool(i & 1<<3)
cmd_verbose = bool(i & 1<<4)
cmd_debug = bool(i & 1<<5)
f = open(hgrc, 'w')
f.write(basehgrc)
f.write('\n[ui]\n')
if hgrc_quiet:
f.write('quiet = True\n')
if hgrc_verbose:
f.write('verbose = True\n')
if hgrc_debug:
f.write('debug = True\n')
f.close()
u = ui.ui()
if cmd_quiet or cmd_debug or cmd_verbose:
u.setconfig('ui', 'quiet', str(bool(cmd_quiet)))
u.setconfig('ui', 'verbose', str(bool(cmd_verbose)))
u.setconfig('ui', 'debug', str(bool(cmd_debug)))
check = ''
if u.debugflag:
if not u.verbose or u.quiet:
check = ' *'
elif u.verbose and u.quiet:
check = ' +'
print ('%2d %5s %5s %5s %5s %5s %5s -> %5s %5s %5s%s'
% (i, hgrc_quiet, hgrc_verbose, hgrc_debug,
cmd_quiet, cmd_verbose, cmd_debug,
u.quiet, u.verbose, u.debugflag, check))